How total of column of a matrix can be kept be same????

If I have a matrix A A=[ 0.4000 0.6000 0.8000 0.8000 1.0000 1.6000 0.9333 1.2333 0.0000 0.0000; 1.2000 0.6000 0.8000 0.8000 1.0000 0.4000 0.5333 0 0 0; 1.2000 1.4000 1.6000 1.6000 1.8000 2.4000 2.5333 2.8333 4.0000 4.0000; 1.2000 1.4000 0.8000 0.8000 0.2000 0 0 0 0 0] I want to keep the total of column to remain same as here the total of each column is as:
sum(A(:,1))
ans =
4
>> sum(A(:,2))
ans =
4
>> sum(A(:,3))
ans =
4
>> sum(A(:,4))
ans =
4
>> sum(A(:,5))
ans =
4
>> sum(A(:,6))
ans =
4.4000
>> sum(A(:,7))
ans =
4
>> sum(A(:,8))
ans =
4.0667
>> sum(A(:,9))
ans =
4
>> sum(A(:,10))
ans =
4
at 6th and 8th column its becoming more than 4 .... so here how can round of this to 4??? plz plz help.....

3 件のコメント

David Sanchez
David Sanchez 2014 年 6 月 12 日
One doubt: Do you want to modify the value of any of the column elements in order to have a column such that sum = 4?
suchismita
suchismita 2014 年 6 月 12 日
yes....if needed some should be deleted to get 4
suchismita
suchismita 2014 年 6 月 12 日
here in my example matrix can you help me in modifying without disturbing the zeros...please...like if in a column sum is more than 4 it should minus the rest and if its less it should add to make it 4... can you help me in that way...

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 採用された回答

Jos (10584)
Jos (10584) 2014 年 6 月 12 日

1 投票

This is called a normalisation procedure.
A = rand(10,6) % some random data
sumA = sum(A,1) % unequal column sums
normfun = @(a,b) 4 * (a/b)
Anorm = bsxfun(normfun, A, sumA) % normalise each column
sum(Anorm,1) % all 4, check!

1 件のコメント

suchismita
suchismita 2014 年 6 月 12 日
thank u so much... but here in my example matrix can you help me in modifying without disturbing the zeros...please...like if in a column sum is more than 4 it should minus the rest and if its less it should add to make it 4... can you help me in that way...

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