excel offset using in matlab question with code in

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Nan Shen
Nan Shen 2011 年 8 月 2 日
my 'month' is in cell A1, my target cell is A2, my code is listed below.
objExcel = actxserver('excel.application');
set(objExcel, 'Visible',1);
sheetName = 'DPLLC';
objSheet = objExcel.Worksheets.get('Item', sheetName);
first_m = objSheet.Range('A:Z').Find('month').offset(2,1).Address;
but give me error like ??? '??? Index exceeds matrix dimensions.'
  5 件のコメント
Oleg Komarov
Oleg Komarov 2011 年 8 月 2 日
With the code button: http://www.mathworks.com/matlabcentral/answers/7885-tutorial-how-to-format-your-question. Thanks, it's already more readable.
Oleg Komarov
Oleg Komarov 2011 年 8 月 2 日
Can't make it work...I suggest to retrieve the address and apply the offset with matlab, you can search one of the submissions on the FEX to do that.

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回答 (1 件)

Fangjun Jiang
Fangjun Jiang 2011 年 8 月 2 日
According to the Excel VB reference, 'Offset' is a property, not a method. But in Excel VB, it seems working like a method, such as ActiveCell.Offset(3,3).Activate. But in MATLAB, 'Offset' is a property of the Range object and it returns the same Range object.
I guess you could get the address first, do the offset and then apply range.
  2 件のコメント
Nan Shen
Nan Shen 2011 年 8 月 2 日
but when I run: first_m = objSheet.Range('A:Z').Find('month').offset(1,1).Address;, it works..., I will try your suggestion.
Fangjun Jiang
Fangjun Jiang 2011 年 8 月 2 日
Yes, but this 'Offset' is always one element, same is for 'Cells'. Try this:
get(objSheet.Range('A:Z').Find('month'),'Value')
get(objSheet.Range('A:Z').Find('month').Offset(1,1),'Value')
get(objSheet.Range('A:Z').Find('month').Cells(1,1),'Value')
They are all the same.

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