LSB in audio stegnography
古いコメントを表示
% Embed message length in the first 16 samples
% (I don't understand how. Can any one explain?)
str = dec2bin(length(message),16);
if length(message) < length(y)
for a = 1 : length(str)
y(a, nbits-1) = str(a);
end
else
disp('error')
end
I don't understand how they are embedding here. Please help me.
1 件のコメント
Walter Roberson
2016 年 3 月 31 日
Note: the proper term is "steganography" not "stegnography"
採用された回答
その他の回答 (2 件)
Muhammad fayyaz
2014 年 4 月 29 日
0 投票
2 件のコメント
Walter Roberson
2014 年 4 月 29 日
Assume that the original signal has been converted into binary by using dec2bin(). dec2bin() returns an array of characters, each one being the character '0' or the character '1'. Then y(a,nbits-1) is a straight forward replacement of one element of the array with one element of the character vector "str".
Somewhere after this section of code, you will find a call to bin2dec(y) . That operation will take the character array y and convert the representation back into decimal numbers.
Muhammad fayyaz
2014 年 4 月 30 日
Muhammad fayyaz
2014 年 5 月 1 日
編集済み: Walter Roberson
2016 年 3 月 31 日
カテゴリ
ヘルプ センター および File Exchange で Numbers and Precision についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!