save only one value

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Tomas
Tomas 2014 年 3 月 13 日
編集済み: Salaheddin Hosseinzadeh 2014 年 3 月 18 日
Hello,
I have for example matrix
MON = [2.8 3.6 17.2;
5.4 8.3 15.8;
2.5 3.2 17.6;
9.9 10.7 13.6;
5.5 8.9 15.5;
9.7 11 13.9;
2.3 3.9 17.9;
5.7 8.1 15.1;
9.4 10.5 13;
9.9 13.2 13.7];
I calculate distance between points from MATRIX.
or i=1:m % pre pocet objektov (pre kazdy riadok MON)
B = MON(i,:); % vloz i-ty riadok z MON do premennej B
for j=1:r % pre kazdy riadok TAZ
ED(j)= distance(TAZ(j,:),B,fff); %euklidovska vzdialenost
[minD, minI(idx)] = min([ED]); %minimalna hodnota a index
end
Then I want to save the smallest value to the cell.
[e,f]=size(ED);
for h=1:f
if (ED(h) == ED(minI(idx)))
Z{h}{z}=B;
z=z+1;
end
end
idx=idx+1;
end
If I have the same value is stored me both to cell. How i stored a just a single valu to cell.
For example ED=[4 4 6] I want only values from position ED(1) save to cell.
Thanks.
  1 件のコメント
Image Analyst
Image Analyst 2014 年 3 月 15 日
Why a cell instead of a regular numerical array which is much much easier to work with?

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回答 (1 件)

Salaheddin Hosseinzadeh
Salaheddin Hosseinzadeh 2014 年 3 月 13 日
Sorry, but even your English is a bit confusing, just like mine! lol Is the problem of having two 4 bothers you?
If so then I guess you can use 'unique' to get rid of the repeated 4
ED= unique(ED,'stable') % this should give you ED=[4,6]
Sorry if I didn't get what's your problem, please explain more what do you want to happen.
Good Luck!
  6 件のコメント
Tomas
Tomas 2014 年 3 月 15 日
編集済み: Tomas 2014 年 3 月 15 日
Yes, I'm sure,
??? Error using ==> unique at 34 Unrecognized option.
Error in ==> KMNS at 262 ED= unique(ED,'stable')
ED is for example ED=[inf NaN NaN] i want to have ED=[inf, NaN]
Salaheddin Hosseinzadeh
Salaheddin Hosseinzadeh 2014 年 3 月 18 日
編集済み: Salaheddin Hosseinzadeh 2014 年 3 月 18 日
First of all so sorry for getting back to you with a huge delay, you're problem is probably solved by now! so sorry
I read through the MATLAB help for 'unique()' and unfortunately it's clearly documented that 'unique treats NaN values as distinct'
So for your example we can't use unique anyway!
If the problem is only with NaN then it's easy
i=1;
NanCount=0;
while(i<= length(ED))
if(isnan(ED(i)))
if(NanCount>0)
ED(i)=[];
i=i-1;
end
NanCount=NanCount+1; % to see how many nan is omitted
end %end of if
i=i+1;
end %end of while
Number of omitted NaNs should equal NanCount-1
Sorry I don't have MATLAB now to try it. Give it a shot and let me know about the result.

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