How can I discretize a function so I can use it in a model?
26 ビュー (過去 30 日間)
古いコメントを表示
I need to use discretized data in my model, but I have three continuous functions for three different time-periods. How can I implement this correctly?
2 件のコメント
Chris C
2014 年 3 月 12 日
Claire, that depends on a few things including: what the functions are, what the model is and what kind of precision you're looking for. If you could clarify a little bit I might be able to help.
採用された回答
Chris C
2014 年 3 月 12 日
The great thing about your question is that you already have the continuous functions. The greater challenge is usually finding a function to represent your data, but since that isn't a problem this shouldn't be too tough. What I would do is create a time array and then solve your continuous functions at every time step within your time array. For example...
t = linspace(1,1000,100); %Generates a time vector from 1 to 1000 with 100 points
x = ones(length(t),3); % Initialize data matrix.
x(:,1) = cos(t); % Solve each equation at each node of the time vector
x(:,2) = 3*t.^2;
x(:,3) = log(t/5);
However, if your function changes rapidly in any zone your discretization should have more data, especially in that region. This might require you to use something like logspace of even to define your own discretization manually.
2 件のコメント
Chris C
2014 年 3 月 12 日
編集済み: Chris C
2014 年 3 月 12 日
This is not the most elegant approach, but it's probably the easiest to understand (at least for me) :)
k = 2;
b = 4;
t = linspace(0,720,721);
x = ones(length(t),1);
for i = 1:length(t)
if t(i)<360-k/2
x(i) = 'INSERT FUNCTION HERE';
elseif t(i) >= 360-k/2 && t(i)<360+k/2
x(i) = 'INSERT FUNCTION HERE';
else
x(i) = 'INSERT FUNCTION HERE';
end
end
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Numeric Types についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!