need you help please please

>> A=[1 2;3 4]; >> B=[9 8 7;6 5 4;3 2 1]; >> a=[11,12] >> b=[21;22]; >> c=[19 18 17]; >> d=[29;28;27];
i am stuck on these questions , i did the rest but really stuck on these question , i spend almost 4 hours playing around with different ways, but can't get the right answer. any help will be much appreciated. Thank you soo much

回答 (2 件)

Mischa Kim
Mischa Kim 2014 年 2 月 23 日
編集済み: Mischa Kim 2014 年 2 月 23 日

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John, for the first one, use
ans1 = [a b'; d B]
it's simply putting together vectors and matrices in the correct order. To get the 1's in the second example, you could use A(1,1), four times. And so on and so forth...

6 件のコメント

john hollywood
john hollywood 2014 年 2 月 23 日
thank you soo much it works , what about part F and G '
Mischa Kim
Mischa Kim 2014 年 2 月 23 日
F works just the same: put together vectors in the correct order. With the prime (') you can turn a column into a row vector, and vice versa.
G: I already showed you how to get 1's. The zero matrix (2-by-2) you get by using A-A .
john hollywood
john hollywood 2014 年 2 月 24 日
編集済み: john hollywood 2014 年 2 月 24 日
for 'part F' i just don't how put number "29" in there. also for 'Part G', i just don't know how to put matrix A in that diagonal form.i did try switch rows and columns and also tried transpos but nothing seems to work. i used diag(diag(A')) But its not working. Thank you soo much
Mischa Kim
Mischa Kim 2014 年 2 月 24 日
編集済み: Mischa Kim 2014 年 2 月 24 日
Here you go:
F = [[A(1,1) A(1,1); A(1,1) A(1,1)] a' b; c d(1)]
G = [A(1,1) A(1,1)-A(1,1) A(1,1) A(1,1)-A(1,1);
A(1,1)-A(1,1) 2*A(1,1) A(1,1)-A(1,1) A(1,1);
[A(1,1) A(1,1); A(1,1) A(1,1)] A-A]
Please post follow-up question and comments as comment, not answers.
Walter Roberson
Walter Roberson 2014 年 2 月 24 日
The "2*" of "2*A(1,1)" violates the constraint of not introducing any new scalars. You could replace the "2*A(1,1)" with A(1,1)+A(1,1)
However, as I read the question, the indices (1,1) would be introduced scalars. Forming the 2 x 2 sub-block of 1's then becomes difficult.
Sagar Damle
Sagar Damle 2014 年 2 月 25 日
I think we are allowed to use scalars as indices but not as extra data.
John,where did you get these questions(from which book)?If they are in a book,are they in 'Exercise' of a chapter?What are the contents of that chapter?(This will help us to narrow our thinking,because exercise of a chapter contains problems related to that chapter.)
Can we use rem(input_matrix,2) to get output in terms of 0's and 1's only?

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john hollywood
john hollywood 2014 年 2 月 24 日

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for 'part F' i just don't how put number "29" in there. also for 'Part G', i just don't know how to put matrix A in that diagonal form.i did try switch rows and columns and also tried transpos but nothing seems to work. i used diag(diag(A')) But its not working. Thank you soo much

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