Regarding Interpolation( vertical)
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I have two data sets in which one is 4D data sets and another one is 2D.
1) first data: 120( longitude) x 90(latitude) x 34 (vertical level) x 8 (Time) 2) second data: 15( vertical level) x 469( number of observations)
I would like to interpolate 34 vertical levels to 15 vertical levels. so somebody knows how to fix this problem?
回答 (2 件)
Sean de Wolski
2011 年 7 月 18 日
A = rand(5,5,34,5);
[ii jj kknew LL] = ndgrid(1:5,1:5,linspace(1,34,15),1:5);
C = interpn(A,ii,jj,kknew,LL);
You could just use interpn directly, thought this will use information from other dimensions.
4 件のコメント
Uday
2011 年 7 月 18 日
Sean de Wolski
2011 年 7 月 18 日
I just did that as an example since I didn't want to kill the RAM on my laptop. For your case:
[ii jj kknew LL] = ndgrid(1:120,1:90,linspace(1,34,15),1:8);
C = interpn(A,ii,jj,kknew,LL);
Also, how do you plane on comparing a 2d matrix 15x469, to a 4d matrix? I think bsxfun/repmat might be necessary. Or do you want to append it?
I.e.
cat(3,A,C)? (in which case you don't even need to interpolate down?
Please clarify the goal.
Uday
2011 年 7 月 19 日
Sean de Wolski
2011 年 7 月 19 日
Show us _exactly_ what you wrote.
Andrei Bobrov
2011 年 7 月 18 日
In = DataInput; % Array 4D
[a b oldc d] = size(In);
newc = 15;
Out = zeros([a b newc d]);
for j4 = 1:d
d1 = reshape(permute(In(:,:,:,j4),[3 2 1]),oldc,[]);
Out(:,:,:,j4) = permute(reshape(cell2mat(arrayfun(@(i1)interp1((1:oldc)',d1(:,i1),linspace(1,oldc,newc)'),1:a*b,'un',0)),newc,b,a),[3 2 1]);
end
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