strcat two char arrays, how to remove the space?

6 ビュー (過去 30 日間)
Zoe Zhang
Zoe Zhang 2011 年 7 月 15 日
I have two char arrays a and b, say
a is a 5*14 char
var =
NKY 08/12/11 C
NKY 08/12/11 C
NKY 08/12/11 C
NKY 08/12/11 C
NKY 08/12/11 C
b is a 5*5 char
val =
5900
5905
5910
5915
5920
If I do strcat(a,b) or [a,b], it gives me
val =
NKY 08/12/11 C 5900
NKY 08/12/11 C 5905
NKY 08/12/11 C 5910
NKY 08/12/11 C 5915
NKY 08/12/11 C 5920
but I need
val =
NKY 08/12/11 C5900
NKY 08/12/11 C5905
NKY 08/12/11 C5910
NKY 08/12/11 C5915
NKY 08/12/11 C5920
Could anyone tell me how to do that? Very appreciated!

採用された回答

Sean de Wolski
Sean de Wolski 2011 年 7 月 15 日
val(:,15) = []; %just delete that column
  3 件のコメント
Sean de Wolski
Sean de Wolski 2011 年 7 月 15 日
the problem is that your "5x5" char, the second input to strcat, is actually a 6x5 char, I believe. It has nothing to do with strcat - it's not adding the zero.
Zoe Zhang
Zoe Zhang 2011 年 7 月 15 日
Thanks again.
Btw, my b is from num2str of a vector of number.

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その他の回答 (2 件)

Fangjun Jiang
Fangjun Jiang 2011 年 7 月 15 日
You either have trailing white space at the end of "a" or leading whitespace at the begining of "b". check out the following functions.
help strtrim
help deblank
  4 件のコメント
Zoe Zhang
Zoe Zhang 2011 年 7 月 15 日
IC, thanks :)
Fangjun Jiang
Fangjun Jiang 2011 年 7 月 15 日
The reason might be that you only showed a small portion of your data.
a=[5900:5:5920,15900];
b=num2str(a')
b =
5900
5905
5910
5915
5920
15900

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Walter Roberson
Walter Roberson 2011 年 7 月 15 日
strcat('NKY 08/12/11 C', strtrim(cellstr(b)))
Note that this allows you to skip the repmat of the constant string.
Note also that this will return a cell array of strings; you can use char() to convert back to a char array.
  1 件のコメント
Zoe Zhang
Zoe Zhang 2011 年 7 月 15 日
Neat and efficient. And the space problem disappear. Thanks a lot!

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