Adding columns to matrix using circshift by auto incrementing

I want to develop a square matrix from a column matrix using circshift. Here is an example code:

z=[0;1;2;3];

x=[z,circshift(z,1),circshift(z,2),circshift(z,3)];

Output: >> x

x =

     0     3     2     1
     1     0     3     2
     2     1     0     3
     3     2     1     0

I have to do similar for the order of 1200 instead of 4 so I want it to be automatic. Can some one please suggest how can I use loop of vector in this case?

Thanks

Answer 1

[Mischa Kim]

You coud use a simple loop:

z          = [0;1;2;3];

z_mat      = zeros(length(z));
z_mat(:,1) = z;

for ii = 2:length(z)
    z_mat(:,ii)= circshift(z,ii);
end

Initializing a matrix ( zeros ) is faster than appending vectors to a matrix.

[saad]

Thankyou very much. I did in same way

Answer 2

[Andrei Bobrov]

z=[0;1;2;3];

x = [z;z];
n = numel(z);
out = x(bsxfun(@minus,(n+1:2*n)',0:n-1));

Answer 3

[saad]

Thanks for your answers, I already solved using these commands: for n=1:1199 Xm(:,n+1) = circshift(b,n); end