Reconstructing the image from specific number of coefficicents
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Hi there!
Alright, so I've been working on this little piece of code to construct an image using specific coefficicents and there's this error I'm getting:
Subscripted assignment dimension mismatch.
So the code goes this way:
j0=128;
M = 2^(-j0);
m=sqrt(M);
I = imread('lena.png');
J = perform_wavelet_transf(I,j0,+1);
n = size(I,1);
J1 = zeros(n);
J1(1:n/4,1:n/4) = J(1:m,1:m);
result = perform_wavelet_transf(J1,j0,-1);
imshow(result,[]);
I'm getting the error at this line: J1(1:n/4,1:n/4) = J(1:m,1:m);
What do you think?
And yes, Thanks alot!!! for your help in advance :)
回答 (1 件)
Amit
2014 年 1 月 19 日
0 投票
One thing I see first is that M = 2^(-128) = 2.93e-39 and thus m = 5.42e-20 m is not an integer, thus J(1:m,1:m) would not work and give you atleast one error.
8 件のコメント
Ayesha
2014 年 1 月 19 日
Amit
2014 年 1 月 19 日
To make this work, m should be equal to n/4.
when you are J1(1:n/4,1:n/4) = J(1:m,1:m), you are copying an mxm matrix to a n/4xn/4 matrix. That would be only possible if m = n/4.
Ayesha
2014 年 1 月 19 日
Amit
2014 年 1 月 19 日
I dont have the image lena on my matlab.
The problem is when you define j0 = 0, m will become 1. That means J(1:m,1:m) is an scalar.
Given n/4 is an positive integer (you need to make sure that), J1(1:n/4,1:n/4) = J(1:m,1:m); will store J(1:m,1:m) scalar in all n/4xn/4 matrix in J1. I am quite certain this is not what you're looking for. I think somewhere in your algorithm (code), something is missing.
Amit
2014 年 1 月 19 日
Also attach the perform_wavelet_transf function. This is not a inbuilt function in matlab.
Amit
2014 年 1 月 19 日
perform_wavelet_trasf has many dependencies which you did not posted.
I am sorry, this is just frustrating.
Amit
2014 年 1 月 19 日
its alright. In a nut shell, I think there is a problem at M = 2^(-j0) which you use to define m = sqrt(M).
Please double check the algorithm that you must be following that this is the correct way to do this.
Ayesha
2014 年 1 月 19 日
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