Methods to make(fit) the samples of two signals for averaging them
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Hello,
I want to get the average of two signals but the number of samples(values) of the two are not equal.One method to make this possible is by using interpolation and here is the demo by Image Analyst for this but the values of the resultant(interpolated)signal are not equal to that of the real signal values.
Can someone explain if there are other methods available to fit the number of samples between two signals.
Thanks.
6 件のコメント
Gova ReDDy
2014 年 1 月 15 日
Amit
2014 年 1 月 16 日
Can you post example data please?
Gova ReDDy
2014 年 1 月 16 日
Image Analyst
2014 年 1 月 16 日
You're not using interp correctly. Check what the first two arguments are supposed to be - it's not what you have.
Amit
2014 年 1 月 16 日
I think what he want is somehow get both data to be of same size, so he can average it. and yeah, the interpolation used in his code is no better than using y=x.
Image Analyst
2014 年 1 月 16 日
I gave him code to make them the same size in http://www.mathworks.com/matlabcentral/answers/111930#answer_120465 and then to average them. He accepted but then he changed it to the code above, which broke it.
回答 (1 件)
Amit
2014 年 1 月 16 日
0 投票
Your s1 and s2 are 1x363 and 1x411 matrixes. Now what you're interpolating is essentially interp1(s1,s1,_blah_) which is simply a straight line. Moreover you're just plotting plot(s1) etc, which is essentially plot(1:length(s1),s1) etc. The problem here is that the number of elements in your matrixes are different and the plot will look like this.
Is there a 'x' values corresponding to s1 and s2?
2 件のコメント
Gova ReDDy
2014 年 1 月 16 日
Okay, in that case I think you can do something like this (if I understand correctly).
In case length(s1)<length(s2), as in your case
s1_x = linspace(1,length(s1),length(s2));
s2_int = interp1(s2_x,s2,1:length(s1));
plot(s1);hold on;plot(s2_x,s2,,'-g');plot(s2_int,'-r');
%%For averaging
avg_s1s2 = mean([s1;s2_int]);
You dont have to interpolate s1 here.
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