Hi I have the following Image of a circle I want to make its edges uniform can any body help ??

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Youssef  Khmou
Youssef Khmou 2013 年 12 月 25 日
編集済み: Youssef Khmou 2013 年 12 月 25 日

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hi,
i tired to write a fast code, try it and see :
I=imread('dcircle.png'); % that image with deformed circle.
X=rgb2gray(I);
N=size(X);
% finding an approximation of the center
% you take where you want start counting
xc=100;
n=0; % number of black pixels vertically descending
for y=1:N(2)
if X(xc,y)>0.70;
n=n+1;
end
end
% the center is then given by :
r=n/4;
yc=N(2)/2;
Y=zeros(N(1),N(2));
for x=1:N(1)
for y=1:N(2)
rt=sqrt(((x-xc)^2)+((y-yc)^2));
if rt>=r
Y(x,y)=1;
end
end
end
figure,subplot(1,2,1), imshow(X),title(' initial');
subplot(1,2,2), imshow(Y), title(' adjusted');

2 件のコメント

Christine Ak
Christine Ak 2013 年 12 月 26 日
Thank U Soo Much ,, it was helpful :D
Image Analyst
Image Analyst 2013 年 12 月 26 日
In the FAQ, the vectorized approach to drawing a circle is shown: http://matlab.wikia.com/wiki/FAQ#How_do_I_create_a_circle.3F. You might want to use that, or at least learn how to do it.

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その他の回答 (1 件)

Image Analyst
Image Analyst 2013 年 12 月 25 日
編集済み: Image Analyst 2013 年 12 月 25 日

0 投票

Get the area and the Equivalent Circular Diameter of the black spot with regionprops. Then use the FAQ or rectangle() to draw a perfect circle.
binaryImage = grayImage < 128;
measurements = regionprops(binaryImage, 'Centroid', 'EquivDiameter');
centroid = [measurements.Centroid]
diameter = measurements.EquivDiameter
% Draw circle in the overlay.
rectangle('Position',[centroid(1)-diameter/2,centroid(2)-diameter/2,diameter, diameter],...
'Curvature',[1,1],'LineWIdth', 2, 'EdgeColor', 'r');
Attached is the full blown demo. Let me know of any difficulties.

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