How to Make a function accept vector inputs

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Chuzymatics Chuzymatics
Chuzymatics Chuzymatics 2013 年 12 月 21 日
コメント済み: Walter Roberson 2017 年 3 月 29 日
function Ml = myseries(t)
n=0;
while (n<10)
Ml = sum(t.^n/(gamma(n + 1)));
n = n+1;
end
The above code runs well as long as the input variable is a scalar; for vectorized inputs, it fails. What might be wrong?
  4 件のコメント
Ben
Ben 2017 年 3 月 29 日
sum(t.^n/(gamma(n + 1))) needs to have a . before the /
Walter Roberson
Walter Roberson 2017 年 3 月 29 日
./ would only be needed if the right hand side, gamma(n+1) was a vector or matrix, but in this context it is a scalar.

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採用された回答

Youssef  Khmou
Youssef Khmou 2013 年 12 月 21 日
You did not specify how the output should be , 1x1 or Nx1 , you can try this way :
function Ml = myseries(t)
n=0;
ctr=1;
while (n<10)
Ml(ctr) = sum(t.^n/(gamma(n + 1)));
n = n+1;
ctr=ctr+1;
end

その他の回答 (2 件)

Walter Roberson
Walter Roberson 2013 年 12 月 21 日
Your current code overwrites all of Ml each time through the "while" loop, and so is unlikely to be doing what you want.
for n = 0 : 9
Ml(n,:) = sum(t.^n/(gamma(n + 1)));
end
  4 件のコメント
Walter Roberson
Walter Roberson 2013 年 12 月 21 日
Right, sorry,
for n = 0 : 9
Ml(n+1,:) = sum(t.^n/(gamma(n + 1)));
end
Chuzymatics Chuzymatics
Chuzymatics Chuzymatics 2013 年 12 月 22 日
I am proud to belong to this community; you all are legends. Many thanks

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Image Analyst
Image Analyst 2013 年 12 月 21 日
編集済み: Image Analyst 2013 年 12 月 21 日
I think you can to what you want to do with one of these functions. Not sure what you want to do so pick one:
function theSum = myseries(t)
% Vectorized method.
n = 1:length(t);
theSum = sum(t.^n ./ (gamma(n + 1)));
function theSum = myseries(t)
% For loop method.
theSum = 0;
for n = 1 : length(t)
theSum = theSum + t(n)^n ./ gamma(n + 1);
end
This does something completely different than the other two answers but I think is what you were actually intending, which is trying to sum a series.
  5 件のコメント
Image Analyst
Image Analyst 2013 年 12 月 23 日
Well he accepted your interpretation so I guess you were right. The Ml(2) was the sum of terms 1 and 2, the Ml(3) was the sum of terms 1, 2, and 3, and the element Ml(N) was term1 + term2 + term3 + term4 +....+termN. I thought he wanted just one sum - the sum of terms 1 through term N - not N sums, but I guess I was wrong.
Youssef  Khmou
Youssef Khmou 2013 年 12 月 23 日
ok

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