creating a diagonal matrix?

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FULYA  SEREF
FULYA SEREF 2013 年 12 月 12 日
回答済み: Jos (10584) 2013 年 12 月 13 日
Hi,
I want to create a diagonal matrix which has the elements like this: q1,q1,q2,q2,...,qm,qm
q is a function and has m different values for m different x-values
Could anyone help me please?
Thank you!

回答 (3 件)

Simon
Simon 2013 年 12 月 12 日
  2 件のコメント
FULYA  SEREF
FULYA SEREF 2013 年 12 月 12 日
thank you very much but as you see I have the elements who are the same for two times. I suppose I need a loop. I can't enter these values by hand. Because first I will define the function q. I need m different values of q for m different x values. And I have to create a matrix whose diagonal is for example; q(1),q(1),q(2),q(2), ,....,q(m),q(m).
Simon
Simon 2013 年 12 月 13 日
So, if you have your function q, what will be the output? Is it a m-element vector? Or just a scalar value?
If you have your m-element vector X, you can do
ind = 1:m;
ind = [ind; ind];
diag(X(ind(:)))
If you get scalars only you have to create it in a loop.

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Sean de Wolski
Sean de Wolski 2013 年 12 月 12 日
diag(q(1,2,3))
And for more info:
doc diag
  1 件のコメント
FULYA  SEREF
FULYA SEREF 2013 年 12 月 12 日
thank you very much but as you see I have the elements who are the same for two times. I suppose I need a loop. I can't enter these values by hand. Because first I will define the function q. I need m different values of q for m different x values. And I have to create a matrix whose diagonal is for example; q(1),q(1),q(2),q(2), ,....,q(m),q(m).

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Jos (10584)
Jos (10584) 2013 年 12 月 13 日
Like this?
q = [10 20 30] ;
q = q(floor(1:.5:numel(q)+.5)) % expand (there are many other ways to do this!)
diag(q)

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