Solving equation by lsqnonlin function gives warning in MATLAB

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Syeda
Syeda 2013 年 11 月 21 日
編集済み: Syeda 2013 年 11 月 24 日
I'm given data for x,y, and z. I am trying to fit a set of data into a model of functional form as described below:
z(x,y) = c1 + c2.* exp(-(c3 .* x)) + c4.* (y.^1);
where c1, c2, c3, c4 are the coefficients to be found.
I tried to use lsqnonlin function but I am getting the message as
lsqnonlin stopped because the final change in the sum of squares relative to its initial value is less than the default value of the function tolerance.
I have following data e.g
% Here x,y are independent variables and z is dependent variable
x= [1 .. 12];
y= [0.001 .. 0.7];
z= [0.996474846 .. 0.432743332];
model = @(c) c(1) + c(2)*exp(-c(3)*x) + c(4)*y - z;
C = lsqnonlin(model, [1 1 1 1])
Why I am getting this message? Any advice.
Thankyou in advance
  3 件のコメント
Syeda
Syeda 2013 年 11 月 21 日
I just want to get four co-efficients. I want to fit a set of data into a model. But, this message confused me!
Syeda
Syeda 2013 年 11 月 21 日
I just want to get an equation by using these co-efficients

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