Help with rowshift needed

2 ビュー (過去 30 日間)
Tom
Tom 2013 年 11 月 13 日
I have narrowed down the problem from my previous question.
I have a for loop
for ashift = 1:n
x = [x(:,1) - x(ashift,1) x(:,2) - x(ashift,2) ...
x(:,3) - x(ashift,3)]
end
which outputs four matrices (when n = 4) like so:
x =
0 0 0
-21.3131 8.6558 -2.5770
-21.3446 15.1527 -11.0297
-14.4331 16.9392 9.8923
x =
21.3131 -8.6558 2.5770
0 0 0
-0.0315 6.4970 -8.4527
6.8800 8.2834 12.4693
x =
21.3446 -15.1527 11.0297
0.0315 -6.4970 8.4527
0 0 0
6.9115 1.7865 20.9220
x =
14.4331 -16.9392 -9.8923
-6.8800 -8.2834 -12.4693
-6.9115 -1.7865 -20.9220
0 0 0
But I need the rows with zeros in to be at the top of the matrix to simplify subsequent calculations, so I am implementing:
rowshift = 0;
for ashift = 1:n
x = [x(:,1) - x(ashift,1) x(:,2) - x(ashift,2) ...
x(:,3) - x(ashift,3)];
x = circshift(x,rowshift)
rowshift = rowshift - 1;
end
However for some reason this changes the order of the output, i.e:
x =
0 0 0
-21.3131 8.6558 -2.5770
-21.3446 15.1527 -11.0297
-14.4331 16.9392 9.8923
x =
0 0 0
-0.0315 6.4970 -8.4527
6.8800 8.2834 12.4693
21.3131 -8.6558 2.5770
x =
0 0 0
14.4331 -16.9392 -9.8923
-6.8800 -8.2834 -12.4693
-6.9115 -1.7865 -20.9220
x =
0 0 0
6.9115 1.7865 20.9220
21.3446 -15.1527 11.0297
0.0315 -6.4970 8.4527
You see the 3rd and 4th matrices are changing order. Can anyone explain why this is happening, and how to stop it from happening?
Kind regards,
Tom

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