strfind when I have more than one row
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K = STRFIND(TEXT,PATTERN)
I am trying to find Pattern in an array of many rows but I am receiving an error : ??? Error using ==> strfind Input strings must have one row
Is there any function taht would substitute strfind in this case?
1 件のコメント
Sean de Wolski
2011 年 6 月 29 日
Does your pattern take up multiple rows?
回答 (4 件)
Matt Fig
2011 年 6 月 29 日
You have a couple of choices with STRFIND. You could loop over the rows, or pad the array with NANs (or other irrelevant value) then reshape to one long string. For example:
A = [1 2 3 4 5 6;7 6 5 6 3 2;1 2 3 4 5 6]
for ii = 1:size(A,1)
L{ii} = strfind(A(ii,:),[5 6]); % Preall if large A.
end
B = [A nan(size(A,1),1)];
strfind(reshape(B.',1,[]),[5 6])
Paulo Silva
2011 年 6 月 29 日
a=['Congratulations'
'to Walter '
'for his 4000 '
'reputation '
'points ']
rc=[];
for r=1:size(a,1)
c=strfind(a(r,:),'Walter');
if ~isempty(c)
rc=[rc; r c]; %just in case the word appears multiple times
end
end
rc %first column is the row and second column is the column where the word is
1 件のコメント
Roland
2011 年 12 月 29 日
This also does not work well. E.g. if one row has multiple matches this will cause an inconsistent dimensions error.
Teja Muppirala
2011 年 6 月 30 日
STRFIND works on cells too:
a=['Congratulations'
'to Walter '
'for his 4000 '
'reputation '
'points '
'WalterWalterWal']
pat = 'Wal'
strfind(cellstr(a),pat)
1 件のコメント
Roland
2011 年 12 月 29 日
This does not work well. E.g. if one row has multiple matches this will cause an inconsistent dimensions error.
Roland
2011 年 12 月 29 日
This is a possible solution ... not perfect though:
%
% Look for a in b. Returns cell array of
% strfind results for each row.
%
% Usage: strfindmultirow(<searchdata>, <searchpattern>);
%
% e.g. if:
%
% a=['Congratulations'
% 'to Walter '
% 'for his 4000 '
% 'reputation '
% 'points ']
%
% rc = strfindmultirow(a, 'a');
%
% yields:
% rc = strfindmultirow(a, 'a')
% ans = [1x2 double] [5] [] [6] []
%
function rc = strfindmultirow(a, b)
rc={};
for r=1:size(a,1)
c=strfind(a(r,:), b);
rc{length(rc) + 1} = c;
end
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