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Plotting of FRF curves

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Shrinivas Gombi
Shrinivas Gombi 2011 年 6 月 27 日
I want to plot FRF vs Frequency graph.I have a matrix 'a' of acceleration & a force matrix 'f' both of 30000X1 size, collected in 3secs with a time step of 0.0001 sec.I am using the following steps to plot FRF. a=[ ]; f=[ ]; ffa=fft(a); fff = fft(f); frf, H=ffa./fff; aH =abs(H); I want to plot FRF vs Frequency graph using log(aH) on Y-axis. Pl tell me how to specify x-axis?
  1 件のコメント
Rick Rosson
Rick Rosson 2011 年 7 月 11 日
Please format your code:
http://www.mathworks.com/matlabcentral/about/answers/

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回答 (2 件)

bym
bym 2011 年 6 月 27 日
  1 件のコメント
Shrinivas Gombi
Shrinivas Gombi 2011 年 6 月 28 日
Dear Sir,
I had only asked this question in that link also.Thank u very much for ur answer.But I have tried many ways of setting x- axis but not getting correctly.I request u to kindly provide me the exact answer.
Prof.S L Gombi

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bym
bym 2011 年 6 月 29 日
Frequency resolution is sampling frequency divided by FFT points. So for a one sided spectrum, it is (directly from the documentation)
NFFT = 2^nextpow2(L); % Next power of 2 from length of y
Y = fft(y,NFFT)/L;
f = Fs/2*linspace(0,1,NFFT/2+1);
you can then plot as
semilogy(f,aH)
or
loglog(f,aH)
  3 件のコメント
bym
bym 2011 年 6 月 29 日
L = 30000; y = aH; NFFT = 32768; Fs = 10000
Shrinivas Gombi
Shrinivas Gombi 2011 年 7 月 5 日
Dear SIr,
Kindly check my steps:
a = [30000X1 readings];
ffa = fft(a);
F =[30000X1 readings];
fff = fft(F);
H = ffa./fff;
aH = abs(H);
L = 30000;
NFFT = 32768;
Fs = 10000;
y = aH;
Y = fft(y,NFFT)/L;
f = Fs/2*linspace(0,1,NFFT/2+1);
semilogy(f,aH)
After the Execution I am getting the following comment
??? Error using ==> semilogy
Vectors must be the same lengths.
Kindly let me know where is the mistake and how to correct it.As I required to submit my PhD thesis at the earliest, pl help me in solving this problem.Waiting for your reply
Prof> Shrinivas Gombi

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