filling a internal value of a matrix

Hi I have the following matrix
I=
0 1 0 0
0 0 1 1
0 1 0 0
0 0 1 0
I want the following output:
0 1 0 0
0 1 1 1
0 1 1 0
0 0 1 0
Is there any easy way to do that,easily?
Thanks

 採用された回答

Matt Fig
Matt Fig 2011 年 6 月 26 日

0 投票

This function will help you: FINDSUBMAT. Here is an example:
I=[0 1 0 0
0 0 1 1
0 1 0 0
1 0 0 0
0 0 1 0
1 0 0 0
0 0 1 0];
idx = findsubmat(I,[1 0 1]'); % Available at the above link...
I(idx+1) = 1
I =
0 1 0 0
0 1 1 1
0 1 0 0
1 0 0 0
1 0 1 0
1 0 1 0
0 0 1 0

その他の回答 (1 件)

Paulo Silva
Paulo Silva 2011 年 6 月 26 日

0 投票

I(6)=1;
I(11)=1;
or
I([6 11])=1

3 件のコメント

Mohammad Golam Kibria
Mohammad Golam Kibria 2011 年 6 月 26 日
What to do if I want to fill all those zeros with of the
form :
1
0
1
=
1
1
1
Walter Roberson
Walter Roberson 2011 年 6 月 26 日
Please give an example of the desired output matrix.
Mohammad Golam Kibria
Mohammad Golam Kibria 2011 年 6 月 26 日
I=
0 1 0 0
0 0 1 1
0 1 0 0
0 0 0 0
0 0 1 0
0 0 0 0
0 0 1 0
output:
0 1 0 0
0 1 1 1
0 1 0 0
0 0 0 0
0 0 1 0
0 0 1 0
0 0 1 0
This is an example, your previous code will work for
this simple matrix, but in case when my matrix is larger
and I dont know where this type of pattern
1
0
1
exists and then replace the middle 0 to 1 as above

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