フィルターのクリア

I'm trying to convert a system from c2d and then from d2c but the results are not the same. Why? There is no delay!

3 ビュー (過去 30 日間)
My system is: s^2/s^3+1 My code is:
num=[1 0 0];
den=[1 0 0 1];
sys=tf(num,den)
sysd=c2d(sys,0.3)
sys2=d2c(sysd)
Why is the "sys" different from the "sys2"? Why a system like this 1/(s+1) gives correct results?
num=[1];
den=[1 1];
sys=tf(num,den)
sysd=c2d(sys,0.3)
sys2=d2c(sysd)

採用された回答

zohar
zohar 2011 年 6 月 23 日
Hi sadel
I execute your code and I got :
Transfer function:
s^2
-------
s^3 + 1
Transfer function:
0.2997 z^2 - 0.6 z + 0.3003
-----------------------------
z^3 - 2.987 z^2 + 3.014 z - 1
Sampling time: 0.3
Transfer function:
s^2 - 6.217e-015 s - 1.066e-014
---------------------------------------
s^3 - 6.106e-015 s^2 - 1.377e-014 s + 1
1.377e-014 is very close to zero !
Isn't it enough ?
  3 件のコメント
Walter Roberson
Walter Roberson 2011 年 6 月 23 日
Polynomial fitting almost always has round-off error.
sadel
sadel 2011 年 6 月 23 日
There is no way I to fix it? Even if I take the coefficients and round them?

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeDynamic System Models についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by