eg: if x=127 and r = 5
1st digit 1+5=6; 2nd digit =2+5=7; 3rd digit = 7+5=12---> 3 (sum of digits 1+2 =3)
then output y= 673
if there are more inputs - consider last one as r and store output as y(1),y(2)...etc
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I am not sure this method can be called a cipher since there is probably no way to recover the original number. You should probably call it a hash.
yeah, that's right. Thanks, I changed it to hash and changed some test cases too.
Clearly, need a new test case to eliminate solutions that define isequal() to always return true.