>> R1=1;L=10e​-3;C1=10e-​6;R2=10; A=[{-R1/L}​{-1/L};{1/​C1}{-1/{R2​*C1}}]; B=[{1/L};0]; C[0 1]; D=[0]; ??? A=[{-R1/L}​{-1/L};{1/​C1}{-1/{R2​*C1}}]; | Error: Unbalanced or unexpected parenthesis or bracket.

回答 (2 件)

Image Analyst
Image Analyst 2013 年 9 月 12 日

1 投票

You can't just place two cells next to each other like that - you need a comma or semicolon to separate them. Try replacing }{ with }, {

2 件のコメント

Image Analyst
Image Analyst 2013 年 9 月 12 日
編集済み: Image Analyst 2013 年 9 月 13 日
Actually I don't know why you're using cells anyway. Why not just use parentheses so you have normal, regular numbers, not cells. Cells are not for the faint of heart beginner MATLAB programmers.
Harry
Harry 2013 年 9 月 13 日
thanks man i got the solution by removing the unnecessary brackets.

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Ilham Hardy
Ilham Hardy 2013 年 9 月 12 日

0 投票

I don't know what you are trying to achieve, but i think you should start with perusing this... http://matlab.wikia.com/wiki/FAQ
R1=1;
L=10e-3;
C1=10e-6;
R2=10;
A=[(-R1/L)*(-1/L);(1/C1)*(-1/(R2*C1))];
B=[(1/L);0];
C=[0 1];
D=0;

4 件のコメント

Harry
Harry 2013 年 9 月 12 日
"A" is a matrix of 2*2 and it is giving a error as I have mentioned earlier
Ilham Hardy
Ilham Hardy 2013 年 9 月 12 日
Did you try my answer?
You need to differentiate the use of curly brackets {} and normal brackets ()
Harry
Harry 2013 年 9 月 12 日
and I am trying to get the step response of R,L,C circuit using steady state equation.
Harry
Harry 2013 年 9 月 13 日
thanks man i got the solution by removing the unnecessary brackets.

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