hi professoinals.....how to run this code

%Calculate the value of e and kp2
p=3
kpi=4
dp = 5
kp2=rand(10); 
e=rand(10);
for i=1:1
    j=1:5
    r=e(j)*dp-kp1*kp2(i)*(p-1)
if r==1
    q1=kp2(i)
    q2=e(j)
    break;
end
end

it doesnot show value of q1 and q2

[Image Analyst]

Please read this: http://www.mathworks.com/matlabcentral/answers/13205-tutorial-how-to-format-your-question-with-markup

Answer 1

[Image Analyst]

That's because r is never 1. Assuming your kpi is really kp1, then your code outputs this:

p =
     3
kp1 =
     4
dp =
     5
j =
     1     2     3     4     5
r =
          -2.2984647062648         -1.68125690365354         -2.35894629559188         -6.49583211445794         -3.95680751584107

As you can see, r is never 1 so this line

if r==1

is never true and you never get to the code that would display q1 and q2.

Answer 2

[Florian]

Hi Neet,

I have absolutely no clue what your code is supposed to do, but there are a couple of syntax proplems with what you have copied. Here is a correction with indents and ";" to show the end of a line:

%if true
%Calculate the value of e and kp2 
p = 3; 
kp1 = 4; 
dp = 5; 
kp2 = rand(10);
e = rand(10); 
for i = 1:1 % This loop is redundant 
  for j = 1:5 
      r = e(j) * dp - kp1 * kp2(i) * (p-1);
      if r == 1 
          q1 = kp2(i); 
          q2 = e(j); 
          break; 
      end
  end 
end
%end

This code runs, BUT: 1) The loop for i is redundant 2) r will likely never be equal to 1 since kp2 and e are defined as random numbers Hence, you won't get any values for q1 and q1. You should probably check what this code is supposed to do.

Cheers, Florian

Answer 3

[rjnt Kaur]

Thanks Florian for your valueable time ...i want to satistisfy the equation e*dp-kp1*kp2*(p-1)=1....my code is not generating r=1..if r is equal to one then the value of e and kp2 is taken..can you suggest other method regarding this...thanking you