parfor indexing and order
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[a,b,c]=size(Mask); % a=b=c=3;
parfor i=1:size(Mask,3)
i
end
I was expecting to see i=1,i=2,i=3 in a sequence as one would see in a for loop but it is giving me i=3,i=2,i=1 . This is in reverse order. I cant figure out the reason.
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Edric Ellis
2013 年 4 月 4 日
0 投票
PARFOR loops can run in parallel, and as such, the iterations might run in any order. You should not rely on this order. In particular, as you have observed, PARFOR starts running iterations in reverse order.
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