How to: Control Histogram bin width

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Hello kity
Hello kity 2013 年 2 月 4 日
Hi
Matlab chooses its own bin width when u use hist().
But I want, for example to make an histogram which makes bins of each 0.5 width. I noticed that hist uses the entire data range as range.
bin_width ( get from edit field)
data=[1:10];
range=max(data)-min(data);
bins= bin_width * range
[n xout]= hist (data, bins)
this still makes random hist where u dont have control over the bins.
what i want is,select the bin_width , 0.5 , plot first bin between 0 - 0.5 , second 0.5- 1 etc.

採用された回答

per isakson
per isakson 2013 年 2 月 4 日
Try
doc histc

その他の回答 (1 件)

Hello kity
Hello kity 2013 年 2 月 4 日
編集済み: Hello kity 2013 年 2 月 4 日
I found an answer at google, adjusted some, hope it is useful.
With this code you can manually select the stepsize of the hist bins, for example, stepsize is 1. then it plots a bin from 0-1 ,1- 2 etc. IT also plots the amount of each bin on top of it.
xStep=str2double(get(handles.xstep1,'String')); % edit field where is used a input for xstep
hist(DATA)
xbounds = xlim;
nBins = (xbounds(2)-xbounds(1))/xStep;
edges = linspace(xbounds(1),xbounds(2), nBins+1);
%# compute center of bins (used as x-coord for labels)
bins = ( edges(1:end-1) + edges(2:end) ) / 2;
%# histc
[counts,binIdx] = histc(DATA, edges);
counts(end-1) = sum(counts(end-1:end)); %# combine last two bins
counts(end) = []; %#
% %# plot histogram
bar(edges(1:end-1), counts, 'histc')
for c=1:numel(counts)
if counts(c)~=0
text(bins(c), counts(c)+0.3, num2str(counts(c)), 'FontWeight','bold', 'FontSize',8, ...
'VerticalAlignment','bottom', 'HorizontalAlignment','center');
end
end
set(gca,'ylim',[0 max(counts)+1/10*(max(counts))]); %adjust ymax
end

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