Structured Cell array assignment question
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If I have something like
A(1).a = {c};
A(2).a = {d};
and
B(1).a = {e};
B(2).a = {f};
and want to assign B.a to A.a,
for i=1:length(A)
A(i).a = B(i).a;
end
is there a way to do this without doing a 'for' loop?
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採用された回答
Walter Roberson
2016 年 1 月 29 日
In the special case where a is the only field in A, but there are potentially additional fields in B, then
A = struct('a', {B.a});
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その他の回答 (1 件)
John BG
2016 年 1 月 29 日
A.a and B.a are type struct. How do you expect to be able to assign B.a=A.a without making sure that the structures have same fields?
The obvious solution is that you build a function, kind of assignstruct(struc1,struc2) and that in this function you first make sure you can copy data from one structure to the other, and if struct1 struct2 are not compatible then return error.
John
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