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need help for take data from loop

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christiano doni
christiano doni 2015 年 4 月 6 日
コメント済み: christiano doni 2015 年 4 月 6 日
I have scrip data like this
clear all;close all;clc
c1=imread('1200TIM-20150401-0010_20150401-1054015001500-1','png');
a1=double(c1);
a1=reshape(a1,2229000,[]);
c2=imread('1200TIM-20150401-0020_20150401-1054015001500-1','png');
a2=double(c2);
a2=reshape(a2,2229000,[]);
c3=imread('1200TIM-20150401-0030_20150401-1054015001500-1','png');
a3=double(c3);
a3=reshape(a3,2229000,[]);
and I have matrix
a1=(2229000,3); a2=(2229000,3); a3=(2229000,3);
and i want to make 3 matrix data like this
red=[a1(:,1),a2(:,1),a3(:,1)]
green=[a1(:,2),a2(:,2),a3(:,2)]
blue=[a1(:,3),a2(:,3),a3(:,3)]
*my questions is how to make loop for red, grean and blue because data a1, a2 until a100, i try *
for i=1:1:3; red(:,i)=['a'num2str(i)(:,1)]; end
but its not working here

採用された回答

Philipp Maier
Philipp Maier 2015 年 4 月 6 日
編集済み: Philipp Maier 2015 年 4 月 6 日
The eval function can be used to execute the MATLAB expression. For example:
for i=1:1:3;
red(:,i)= eval(['a' num2str(i) '(:,1)'])';
end
Since I do not have the PNG-files that you are reading , I tested the code with three random variables:
a1 = rand(2229000,3);
a2 = rand(2229000,3);
a3 = rand(2229000,3);
  1 件のコメント
christiano doni
christiano doni 2015 年 4 月 6 日
ah ...thank you sir...it's working here

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その他の回答 (1 件)

Jan
Jan 2015 年 4 月 6 日
No, do not do this. It might work in this specific case, but it is in general an evil method and it produces more troubles than it solves. The problem is discussed several times a day and therefore you find it in the frequently asked questions also: http://www.mathworks.com/matlabcentral/answers/57445-faq-how-can-i-create-variables-a1-a2-a10-in-a-loop .
  1 件のコメント
christiano doni
christiano doni 2015 年 4 月 6 日
ok sir, move to you link.. thanks for you advice

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