Replace values in a array

8 ビュー (過去 30 日間)
Miguel Albuquerque
Miguel Albuquerque 2022 年 7 月 18 日
コメント済み: Miguel Albuquerque 2022 年 7 月 18 日
Hey guys, thanks in advance, this is probably very easy
What I need to do, is find where y_max is not zero, and see where the values from it are equal to range, a bigger array, but that has in some columns the same values of y_max.
Next I need to replace the columns where range has the same values of y_max by the values of RMC that are not zero.
How can I do that, thanks. Because its mandatory that all columns of b be replaced by isR2, but isR2 has more values that b, but for isR2 i want to select number os values of b, because RMC has the same values along the array.
I have this code:
isR=find(y_max);
isR2=find(RMC);
y_cutted=y_max(isR);
[a,b]=intersect(range,y_cutted);
b=b.';
range(:,b)=RMC(:,isR2);
But i get this error
Unable to perform assignment because the size of the left side is 1-by-69 and the size of the right side is 1-by-93.
  1 件のコメント
Miguel Albuquerque
Miguel Albuquerque 2022 年 7 月 18 日
basically I need to do this, but automatic:
isR=find(y_max);
y_cutted=y_max(isR);
[a,b]=intersect(range,y_cutted);
b=b.';
RMC=RMC(:,184:255);
range(:,(254:325))=RMC;

サインインしてコメントする。

回答 (1 件)

David Hill
David Hill 2022 年 7 月 18 日
Attaching the data would help.
range(ismember(range,y_max(y_max~=0)))=RMC(RMC~=0);
  1 件のコメント
Miguel Albuquerque
Miguel Albuquerque 2022 年 7 月 18 日
sorry, here it is , it gives an error your code
Unable to perform assignment because the left and right sides have a different number of elements.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeMultidimensional Arrays についてさらに検索

タグ

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by