How to find index of first 3 maximum number in matrix

I have the following function that n is the first 3 maximum value of matrix m:

m = [7;1;4;4;12;2;6;10;2];
temp = sort( m, 'descend' );
n = temp(1:3)

I need to know the index of matrix n, like:

p = [5;8;1]; % first max value in matrix m is 12 that it located in the fifth row

Answer 1

[Orion]

use the second output argument of sort

m = [7;1;4;4;12;2;6;10;2];
[temp,originalpos] = sort( m, 'descend' );
n = temp(1:3)
p=originalpos(1:3)

[Amit Kumar]

Great.. I just want to add a comment that if you have NaN in your matrix replace beforehand as m(isnan(m))=0 and then use, as:

m = [7;1;4;4;NaN;2;6;10;2];

m(isnan(m))=0

[temp,originalpos] = sort( m, 'descend' );

n = temp(1:3)

p=originalpos(1:3)

Answer 2

[Aida Arman]

maxk(m,3)

maxk in Mathworks

Answer 3

[MA]

m = [7;1;4;4;12;2;6;10;2];
temp = sort( m, 'descend' );
n = temp(1:3);
for i=1:9
    if n(1)==m(i)
        p1=i;
    elseif n(2)==m(i)
        p2=i;
    elseif n(3)==m(i)
        p3=i;
    end
end
p=[p1 p2 p3]