How to remove duplicate NaN values from an X Y data set

I have a large data set a simplified version is data=[1,2;3,4;nan,nan;5,6;nan,nan;nan,nan;10,11]. I need to remove any rows of NaN that are repeated more than once so the above example would become data=[1,2;3,4;nan,nan;5,6;nan,nan;10,11]. The sequence is important

     1     2
     3     4
   NaN   NaN
     5     6
   NaN   NaN
   NaN   NaN
    10    11

should become

     1     2
     3     4
   NaN   NaN
     5     6
   NaN   NaN
    10    11

Answer 1

[Andrei Bobrov]

data=[1,2;3,4;nan,nan;5,6;nan,nan;nan,nan;7,8];

d = all(isnan(data),2);
n = [0;diff(d)];
k = find(n == -1);
m = find(n == 1);
d = d + 0;
d(k) = m(1:numel(k)) - k;
out = data(cumsum(d) <= 1,:)

other way

data=[1,2;3,4;nan,nan;5,6;nan,nan;nan,nan;7,8];

d = all(isnan(data),2);
data(strfind(d(:)',[1,1]),:) = [];

[Evan]

thank you very much works exactly as needed

Answer 2

[Hikaru]

There might be more efficient ways to do this, but the following code works.

data=[1,2;3,4;nan,nan;5,6;nan,nan;nan,nan;10,11]
data(isnan(sum(data,2)),:)=[]

[Evan]

Thanks Hikaru, this is not the outcome I need. The data set must still contain NaN but no sequential duplicates, the output I require is in my original post labeled 'should become'. Thanks again.

[Hikaru]

Sorry, didn't catch that earlier. Maybe you can use this approach.

a=[1,2;3,4;nan,nan;5,6;nan,nan;nan,nan;10,11];     
[r,c] = size(a)
b = reshape(a,1,r*c)

ind = isnan(a(:))'
repeatednan = strfind([0, ind], [1 1])
b(repeatednan)=[]
reshape(b,r-length(repeatednan)/2,c)