Hello, I have a dataset called NO2 and vector of site IDs called SNO2. If a value in the 4th column of the data set (MonitorID) is contained in SNO2 I want to delete the entire row from the dataset. The dataset looks like this
INPUT_FID NEAR_FID DISTANCE MonitorID StationID Classification 14 18 0.137058 60711004 60712002 3
This is the code that I have written. I keep getting an error message that says the index of the matrix to remove exceeds the matrix dimensions. Thanks!
NO2=double(NO2);
for i=1:length(SNO2)
M=find(NO2(:,4)==SNO2(i))
NO2(M,:)=[]
end

 採用された回答

the cyclist
the cyclist 2014 年 10 月 15 日

0 投票

You can avoid the for loop altogether:
M = ismember(NO2(:,4),SNO2);
NO2(M,:)=[];

1 件のコメント

Rachel
Rachel 2014 年 10 月 15 日
Thanks so much this works perfectly!

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その他の回答 (2 件)

Yu Jiang
Yu Jiang 2014 年 10 月 15 日

0 投票

This means M is larger than the number of rows in NO2. After you see the error message, type M in the command window to see what is the value of it, and then compare it with size(NO2).
Image Analyst
Image Analyst 2014 年 10 月 15 日

0 投票

The only thing I noticed off the top of my head was that if SNO2(i) was not found, M could be empty and you don't take that into consideration, like
if ~isempty(M)
% Found the number in column 4 of NO2.
% Delete those rows with that number.
NO2(M, :) = [];
end
I think you can do this whole loop without a loop is you use ismember().

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