How to use for loop to get the minimum number in an array

For simplicity, I have

 A=[ 11 7 10 9 6 4 3]

and

 B=8

I want to have a for loop to compare each of the elements in A with the latest minimum number from the for loop to get the final minimum number in A.

For example, when A(1) compare with B, min=8, then i continue with the A(2) compare with min=8, this time min=7. After that, A(3) compare with min=7, new min=7. The steps continue till the last elements of A.

Answer 1

[Jos (10584)]

A = [ 11 7 10 9 6 4 3]
B = 8
result = min([A B])

% or if you insist on using a for-loop (why?)

result = B
for k = 1:numel(A)
   if A(k) < result,
     result = A(k)
   end
end

Answer 2

[Abhishek M]

Hi Grace, I guess this is what you are expecting. Please find the demo example below.

a=[1:2:10];
b=4;
for i=1:5
if a(i)<b
  min=b;
else 
  min=a(i);
end
end