function Y = myFunc(P,P0)
N = 2;
Pa = 9;
k = floor((P0*N/Pa));
Y = F(P)+k*F(N*P0-P*k);
function Fp = F(P)
R = 3;
beta = 8;
Fp = 1 - exp(-((2^R-1)./P).^(beta/2));
%Step 2: Minimize it within the bounds:
P0 = 9;
[Pi, FVal] = fminbnd(@(x) myFunc(x,P0),0,7);
getting error: Error using myFunc (line 4)
Not enough input arguments.

 採用された回答

Mischa Kim
Mischa Kim 2014 年 1 月 28 日

0 投票

Hello Shobi, code looks fine. Make sure to save the two functions in one function file (called myFunc.m). Then execute the two final commands in the MATLAB command window:
P0 = 9;
[Pi, FVal] = fminbnd(@(x) myFunc(x,P0),0,7);

10 件のコメント

shobi swaminathan
shobi swaminathan 2014 年 1 月 28 日
which two functions.....
Youssef  Khmou
Youssef Khmou 2014 年 1 月 28 日
編集済み: Youssef Khmou 2014 年 1 月 28 日
hi, means the function called F is a subfunction of the main myFunc.
Mischa Kim
Mischa Kim 2014 年 1 月 28 日
I mean, put
function Y = myFunc(P,P0)
N = 2;
Pa = 9;
k = floor((P0*N/Pa));
Y = F(P)+k*F(N*P0-P*k);
function Fp = F(P)
R = 3;
beta = 8;
Fp = 1 - exp(-((2^R-1)./P).^(beta/2));
in one function called myFunc.m.
shobi swaminathan
shobi swaminathan 2014 年 1 月 28 日
After saving the code as myFunc.m if we run then the following error is shown
Error using myFun (line 4) Not enough input arguments
shobi swaminathan
shobi swaminathan 2014 年 1 月 28 日
編集済み: shobi swaminathan 2014 年 1 月 28 日
Then if we type
P0 = 7;
[Pi, FVal] = fminbnd(@(x) myFunc(x,P0),0,7); in the command window following error is shown
Maximum recursion limit of 500 reached. Use set(0,'RecursionLimit',N) to change the limit. Be aware that exceeding your available stack space can crash MATLAB and/or your computer. Error in myFunc>F
Mischa Kim
Mischa Kim 2014 年 1 月 28 日
編集済み: Mischa Kim 2014 年 1 月 28 日
So it looks like it works (it works just fine on my machine). What MATLAB release are you working with?
What happens if you execute
[Pi, FVal] = fminbnd(@(x) myFunc(x,P0),0,1.1)
instead?
shobi swaminathan
shobi swaminathan 2014 年 1 月 28 日
I am using matlab version 2013
Again error
Undefined function 'bs' for input arguments of type 'double'. Error in @(x)bs(x,P0)
Error in fminbnd (line 216) x= xf; fx = funfcn(x,varargin{:});
Mischa Kim
Mischa Kim 2014 年 1 月 28 日
Sorry that was a typo: bs is supposed to be myFunc. Fixed in the above comment.
shobi swaminathan
shobi swaminathan 2014 年 1 月 28 日
Thanks...we are getting the output....
But this code was taken from this website....
We are getting two values Pi and Fval Which one should we take it as minimum...what does Fval means
Mischa Kim
Mischa Kim 2014 年 1 月 28 日
Pi is the x-value you are searching for, FVal is the function value that is minimized at x = Pi.

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その他の回答 (1 件)

shobi swaminathan
shobi swaminathan 2014 年 1 月 28 日

0 投票

Thanks alot.. in the above code the value of P and P0 are fixed.. but in our problem the value of P
and P0 should be as follows
P0 varies from 1 to 10 and
P belongs to P1 such that P1= [0, Pb]∪ ((N*P0)/(k+1)). how to modify the above code to satisfy
these conditions

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