[ASK] Euclidean Distance
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how to find the distance between a webcam with an object ..?
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Christopher Jones
2013 年 10 月 29 日
0 投票
That's a rather general and open ended question. Care to elaborate?
11 件のコメント
Malta
2013 年 10 月 29 日
Image Analyst
2013 年 10 月 29 日
Then I think a tape measure or a scale/ruler would be the most appropriate tool to set up the distance between your camera and your subject (the id card).
Malta
2013 年 10 月 29 日
Walter Roberson
2013 年 11 月 7 日
You appear to have a known distance of "10cm". Is that the distance between the webcam and the ID card? Or is that the known physical distance between two items on the ID card? Are you trying to find the distance between the webcam and the ID card, or are you trying to find the "real-world" size of the ID card, or do you know the real size of the ID card and are trying to find the distance between two items on it, or something else?
Malta
2013 年 11 月 8 日
Walter Roberson
2013 年 11 月 8 日
What information do you have that is known ahead of time, other than that the id card is between 10cm and 20cm away from the webcam? For example, is the entire id card certain to be visible within the image, and is the ID card a known size?
Malta
2013 年 11 月 8 日
Walter Roberson
2013 年 11 月 9 日
Wait -- do you have a fixed size but moving object, and you want to capture the image only if the object is between 10 cm and 30 cm away?
Malta
2013 年 11 月 9 日
Walter Roberson
2013 年 11 月 9 日
Is the ID card a fixed size?
Image Analyst
2013 年 11 月 8 日
0 投票
Malta, like I said, just use a ruler to position your webcam about 10 cm from your card. Make sure that that you can still get an image that is in focus, because that is pretty close and it might be blurry. So once you have that you need to spatially calibrate your scene before you can make laterla measurements from it. For that, please see my calibration demo attached below (simply copy and paste and run).
3 件のコメント
Malta
2013 年 11 月 8 日
Sean de Wolski
2013 年 11 月 8 日
doc bwdist
bwdist has a euclidean option. I don't see how it'll help you (as IA has pointed out).
Image Analyst
2013 年 11 月 8 日
Malta: In the code you'll see the line:
lineLength = round(sqrt((xi(1)-xi(2))^2 + (yi(1)-yi(2))^2))
so I did use Euclidean distance.
At this point I don't know how to help you because after many questions we still don't know what you want to take the Euclidean distance of: the distance from your camera to the card, or laterally between two points on the card.
Moreover, I don't know what level of coding I can give you. If I give you something simple, like the line above, it's basically useless because you'll need other code to get the x and y coordinates. But if I give you code for that, like in the attached short and simple example, you say it's too complicated for your to understand. I don't know how to give you anything in between that would be usable by you. For example I could hard code x and y like this:
x = [2 4];
y = [5 9];
lineLength = sqrt((x(1)-x(2))^2 + (y(1)-y(2))^2))
but that's not really any help to you because those x and y are not what you'll be using, so then you're basically going to have to do something like I gave in the example, which you said was too difficult to understand. I'm sorry that I'm not able to find the right level of complexity that you will be able to understand, and at the same time be useful to you.
Walter Roberson
2013 年 11 月 8 日
0 投票
With that set-up it is not possible to find "distance between webcam with an object", "using euclidean distance". If an object in an image is 100 pixels long, you cannot tell if the object was 100 units long photographed at 10 cm, or 200 units long photographed at 20 cm.
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