Community Profile

photo

Koushik Vemula

MathWorks

Last seen: 4年弱 前 |  2020 年からアクティブ

Followers: 0   Following: 0

I am Applicant Support Engineer at MathWorks. My responsibility is to provide the best support for an application like ML, Computer Vision, Image Processing, and Signal Processing.
Disclaimer: Any articles/ideas/opinions here are my own and in now way reflect that of MathWorks.

統計

  • Knowledgeable Level 2
  • First Answer

バッジを表示

Feeds

表示方法

回答済み
Optimtool not enough arguments
According to my understanding you are facing this problem because of the way you are trying to access the function. You need...

約4年 前 | 0

回答済み
Can I derive a dependent variable in Matlab?
According to my understanding you want to create a variable ‘y’ which is dependent on variable ‘x’ You can do it using ‘syms’...

約4年 前 | 1

| 採用済み

回答済み
cumulative maximum loss code
According to my understanding you have a variable ‘x’ which has ‘n’(say) number of values. You would like to find the value of...

約4年 前 | 0

回答済み
Make probability matrix from data set
According to my understanding, you’d like to have a matrix (say ‘Prob’) which stores the data values in an n-by-3 matrix where f...

約4年 前 | 0

回答済み
how to access compass formatting details?
In MATLAB there is a "polarplot" function that allows you to update the properties of the polar axes. Please see the following d...

約4年 前 | 1

回答済み
How can I convert this pseudo code to matlab?
According to what I understand the pseudo code you’ve written is correct with some minor points to be taken under consideration....

約4年 前 | 0

回答済み
Manipulating matrix with 'for' loop
According to what I understand you want to change the values of 'main diagonal’ and ‘adjacent diagonals’ of the given matrix. ...

約4年 前 | 0

回答済み
Find n for inverse of e approximation
According to what I understand, you are trying to get the value of ‘accurate_n’ which gives you a tolerance of ‘0.0001’. The pro...

約4年 前 | 0

| 採用済み

回答済み
How to take a derivative of x with respect to time.
According to what I understand, you are trying to get the differentiation of variable ‘o’ with respect to the parameter ‘t’. ...

約4年 前 | 0

回答済み
Why does x(x+y) dy give a x^3 component?
Both answers are correct. d/dy[ x*(x+y)^2/2 ] = d/dy[ (x^3)/2 + x^2*y + y^2*x/2 ] = x*(x + y) d/dy[ x*y*(2*x+y))/2 ] = x*(x ...

約4年 前 | 3

| 採用済み