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coordinate edge of the ceramic into pixel (x,y)
try this .. a=imread() ; a=rgb2ycbcr(a); a=a(:,:,2); a=edge(a,'canny',[0.1 0.5],15); you can get the coordinates using fin...

14年弱 前 | 0

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find guite the same elements
let say you have 2 vector A ,B (like your columns there) you can do something like : [C, ia] = unique(A); for k = 1:length(ia...

14年弱 前 | 0

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Cut an area in the image
you can choose top left and bottom left boundaries using range=ginput(2); and then image=image(range(1,2):range(2,2),range(1...

14年弱 前 | 0

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Clustering
try imopen with strel('line',rho,theta)

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How can i calculate e^A*t
exp(A.*t)

14年弱 前 | 1

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Getting rid of lots of thin black lines on an image
You can use, find() , something like this : [r,c,v]=find(bmpimage==0); for i=1:size(r) bmpimage(r(i),c(i))=(bmpim...

14年弱 前 | 0

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質問


close lines after edge detection
Hi all, After edge detection and adding some circular object, I like to close the lines and fill each area. this is an example...

14年弱 前 | 2 件の回答 | 1

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imwrite to full (screen) size
Hi all, Im using imwrite to save images to disk and then later on imread, im2frame and movie2avi to create an avi movie file. ...

14年弱 前 | 1 件の回答 | 0

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OUT OF MEMORY
Hi all, I want to work on an image, but without reducing the resolution by much (for now I use imresize ()).without using it I...

14年弱 前 | 1 件の回答 | 0

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Time difference between images.
Figured it out .. datenum (or the Serial Date Number) gives the fractional number of days from a specific date and time. so I ca...

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Time difference between images.
Hi all, is there an easy way to get the difference in the time an image was taken between 2 jpg files? and what datenum number...

14年弱 前 | 2 件の回答 | 0

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finding rotation of angle
you can use imrotate() running over angles and subtract the result with the original image until you get a zero matrix.

約14年 前 | 0

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Help removing unwanted lines from image and identify spots
After some enhancement I get the following image: <http://i44.tinypic.com/2jfwsnd.jpg> I want to identify the spots which clea...

約14年 前 | 1 件の回答 | 1

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