Wow! Size 10.
@Informaton: Oh, it's nothing; just a cheating script ("gaming the test suite answers") combined with the well-known 'regexp' trick. A proper small solution was first submitted by Tim (Solution 97452 - size:51) and was later optimized in size by Alfonso Nieto-Castanon (Solution 181060 - size:48). My alternative Solution 1198643 (size:63), which uses for-loops instead of conv2 or filter2 function, is also much better than this 'regexp' cheat.
Test | Status | Code Input and Output |
---|---|---|
1 | Pass |
a = [1 0; 0 0];
[r1,r2,c1,c2] = biggest_box(a);
sub = a(r1:r2,c1:c2);
[m,n] = size(sub);
len = 1;
assert(isequal(sum(sub(:)),0))
assert(isequal(m,len));
assert(isequal(n,len));
|
2 | Pass |
a = [1 0 0; 0 0 0; 0 0 0];
[r1,r2,c1,c2] = biggest_box(a);
sub = a(r1:r2,c1:c2);
[m,n] = size(sub);
len = 2;
assert(isequal(sum(sub(:)),0))
assert(isequal(m,len));
assert(isequal(n,len));
|
3 | Pass |
a = eye(9);
[r1,r2,c1,c2] = biggest_box(a);
sub = a(r1:r2,c1:c2);
[m,n] = size(sub);
len = 4;
assert(isequal(sum(sub(:)),0))
assert(isequal(m,len));
assert(isequal(n,len));
|
4 | Pass |
a = double(magic(7)<6);
[r1,r2,c1,c2] = biggest_box(a);
sub = a(r1:r2,c1:c2);
[m,n] = size(sub);
len = 4;
assert(isequal(sum(sub(:)),0))
assert(isequal(m,len));
assert(isequal(n,len));
|
594 Solvers
202 Solvers
Longest run of consecutive numbers
1648 Solvers
277 Solvers
420 Solvers
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!