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x.\u003c/p\u003e","function_template":"function v = canon(g,x)\r\n  v = x;\r\nend","test_suite":"%%\r\ng=32; h=10000;\r\nv_correct = 800;\r\nassert(isequal(canon(g,h),v_correct))\r\n\r\n%%\r\ng=32; h=100;\r\nv_correct = 80;\r\nassert(isequal(canon(g,h),v_correct))\r\n\r\n%%\r\ng=32; h=4;\r\nv_correct = 16;\r\nassert(isequal(canon(g,h),v_correct))\r\n","published":true,"deleted":false,"likes_count":2,"comments_count":2,"created_by":166,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":322,"test_suite_updated_at":"2012-01-28T10:10:54.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2012-01-28T10:10:54.000Z","updated_at":"2026-02-05T16:30:09.000Z","published_at":"2012-01-28T10:10:54.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eGiven g (acceleration due to gravity) and desired altitude x, find the minimum ground velocity of a cannon ball to reach x.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray 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false.","description_html":"\u003cp\u003e\u0026#128640 Imagine a non-relativistic simple situation.\u003c/p\u003e\u003cp\u003eAssume positions p0, p1, p2, and p3 are three dimensional Cartesian coordinates.\u003c/p\u003e\u003cp\u003eYour spacecraft started from the position p0 at time t0.\u003c/p\u003e\u003cp\u003eYour spacecraft is moving with a constant velocity.\u003c/p\u003e\u003cp\u003eYour spacecraft is expected to reach a star at the location p1 at time t1.\u003c/p\u003e\u003cp\u003eYou just heard over the radio that an asteroid has been identified at the location p2 at time t0.\u003c/p\u003e\u003cp\u003eThe asteroid is moving with a constant velocity.\u003c/p\u003e\u003cp\u003eThe asteroid is expected to reach another star at the location p3 at time t1.\u003c/p\u003e\u003cp\u003eYou need to write a code 'safetrip' in MATLAB to return true if the minimum distance between your spacecraft and the asteroid will be more than the distance d during the time interval between t0 and t1, otherwise return false.\u003c/p\u003e","function_template":"function ok = safetrip(d, t0, t1, p0, p1, p2, p3)\r\n    if d\u003e1000000000\r\n        ok = true;\r\n    end\r\nend","test_suite":"%%\r\np0 = [0 0 0];\r\np1 = [1 1 1];\r\np2 = [2 2 2];\r\np3 = [3 3 3];\r\nt0 = 0; \r\nt1 = 1;\r\nd = 1;\r\nok = true;\r\nassert(isequal(safetrip(d, t0, t1, p0, p1, p2, p3), ok))\r\n\r\n%%\r\np0 = [3 3 3];\r\np1 = [2 2 2];\r\np2 = [2 2 2];\r\np3 = [3 3 3];\r\nt0 = 0; \r\nt1 = 1;\r\nd = 1;\r\nok = false;\r\nassert(isequal(safetrip(d, t0, t1, p0, p1, p2, p3), ok))\r\n\r\n%%\r\np0 = [1 2 3];\r\np1 = [4 5 6];\r\np2 = [3 2 1];\r\np3 = [6 5 4];\r\nt0 = 10; \r\nt1 = 20;\r\nd = 2;\r\nok = true;\r\nassert(isequal(safetrip(d, t0, t1, p0, p1, p2, p3), ok))\r\n\r\n","published":true,"deleted":false,"likes_count":6,"comments_count":8,"created_by":166,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":168,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":35,"created_at":"2017-10-10T02:30:44.000Z","updated_at":"2026-03-26T15:11:20.000Z","published_at":"2017-10-16T01:51:00.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml 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velocity.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe asteroid is expected to reach another star at the location p3 at time t1.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYou need to write a code 'safetrip' in MATLAB to return true if the minimum distance between your spacecraft and the asteroid will be more than the distance d during the time interval between t0 and t1, otherwise return false.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" 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false.","description_html":"\u003cp\u003e\u0026#128640 Imagine a non-relativistic simple situation.\u003c/p\u003e\u003cp\u003eAssume positions p0, p1, p2, and p3 are three dimensional Cartesian coordinates.\u003c/p\u003e\u003cp\u003eYour spacecraft started from the position p0 at time t0.\u003c/p\u003e\u003cp\u003eYour spacecraft is moving with a constant velocity.\u003c/p\u003e\u003cp\u003eYour spacecraft is expected to reach a star at the location p1 at time t1.\u003c/p\u003e\u003cp\u003eYou just heard over the radio that an asteroid has been identified at the location p2 at time t0.\u003c/p\u003e\u003cp\u003eThe asteroid is moving with a constant velocity.\u003c/p\u003e\u003cp\u003eThe asteroid is expected to reach another star at the location p3 at time t1.\u003c/p\u003e\u003cp\u003eYou need to write a code 'safetrip' in MATLAB to return true if the minimum distance between your spacecraft and the asteroid will be more than the distance d during the time interval between t0 and t1, otherwise return false.\u003c/p\u003e","function_template":"function ok = safetrip(d, t0, t1, p0, p1, p2, p3)\r\n    if d\u003e1000000000\r\n        ok = true;\r\n    end\r\nend","test_suite":"%%\r\np0 = [0 0 0];\r\np1 = [1 1 1];\r\np2 = [2 2 2];\r\np3 = [3 3 3];\r\nt0 = 0; \r\nt1 = 1;\r\nd = 1;\r\nok = true;\r\nassert(isequal(safetrip(d, t0, t1, p0, p1, p2, p3), ok))\r\n\r\n%%\r\np0 = [3 3 3];\r\np1 = [2 2 2];\r\np2 = [2 2 2];\r\np3 = [3 3 3];\r\nt0 = 0; \r\nt1 = 1;\r\nd = 1;\r\nok = false;\r\nassert(isequal(safetrip(d, t0, t1, p0, p1, p2, p3), ok))\r\n\r\n%%\r\np0 = [1 2 3];\r\np1 = [4 5 6];\r\np2 = [3 2 1];\r\np3 = [6 5 4];\r\nt0 = 10; \r\nt1 = 20;\r\nd = 2;\r\nok = true;\r\nassert(isequal(safetrip(d, t0, t1, p0, p1, p2, p3), 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version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u0026amp;#128640 Imagine a non-relativistic simple situation.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eAssume positions p0, p1, p2, and p3 are three dimensional Cartesian coordinates.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYour spacecraft started from the position p0 at time t0.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYour spacecraft is moving with a constant velocity.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYour spacecraft is expected to reach a star at the location p1 at time t1.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYou just heard over the radio that an asteroid has been identified at the location p2 at time t0.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe asteroid is moving with a constant 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