Cody

# Problem 80. Test for balanced parentheses

Solution 112929

Submitted on 15 Jul 2012 by Jan
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.

### Test Suite

Test Status Code Input and Output
1   Pass
%% inStr = '()'; out_correct = true; assert(isequal(isBalanced(inStr),out_correct))

pos1 = 1 pos2 = 2 pos = 1 out = 1

2   Pass
%% inStr = ')'; out_correct = false; assert(isequal(isBalanced(inStr),out_correct))

pos1 = [] pos2 = 1 pos = [] out = 0

3   Pass
%% inStr = '(z*(a-(x+3))/(y))'; out_correct = true; assert(isequal(isBalanced(inStr),out_correct))

pos1 = 1 4 7 14 pos2 = 11 12 16 17 pos = 10 8 9 3 out = 1

4   Pass
%% inStr = ')('; out_correct = false; assert(isequal(isBalanced(inStr),out_correct))

pos1 = 2 pos2 = 1 pos = -1 out = 0

5   Pass
%% inStr = '(x)(x-y)'; out_correct = true; assert(isequal(isBalanced(inStr),out_correct))

pos1 = 1 4 pos2 = 3 8 pos = 2 4 out = 1

6   Pass
%% inStr = ':-)'; out_correct = false; assert(isequal(isBalanced(inStr),out_correct))

pos1 = [] pos2 = 3 pos = [] out = 0

7   Pass
%% inStr = ')()'; out_correct = false; assert(isequal(isBalanced(inStr),out_correct))

pos1 = 2 pos2 = 1 3 pos = -1 1 out = 0

8   Pass
%% inStr = '(()'; out_correct = false; assert(isequal(isBalanced(inStr),out_correct))

pos1 = 1 2 pos2 = 3 pos = 2 1 out = 0