Cody

# Problem 71. Read a column of numbers and interpolate missing data

Solution 2083608

Submitted on 8 Jan 2020 by Yoshimasa Nakatani
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.

### Test Suite

Test Status Code Input and Output
1   Pass
s = { ... 'Day Temp' ' 1 1.3' ' 2 1.12' ' 3 17' ' 4 -32' ' 5 13' ' 6 4.4' ' 7 19'}; t_correct = [1.3 1.12 17 -32 13 4.4 19]; assert(isequal(read_and_interp(s),t_correct));

str = 7×1 cell array {' 1 1.3' } {' 2 1.12'} {' 3 17' } {' 4 -32' } {' 5 13' } {' 6 4.4' } {' 7 19' } y = 1.3000 y = 1.1200 y = 17 y = -32 y = 13 y = 4.4000 y = 19 pos = 1×0 empty double row vector t = 1.3000 1.1200 17.0000 -32.0000 13.0000 4.4000 19.0000

2   Pass
s = { ... 'Day Temp' ' 1 1.3' ' 2 1.12' ' 3 17' ' 4 16' ' 5 9999' ' 6 9999' ' 7 19'}; t_correct = [1.3 1.12 17 16 17 18 19]; assert(isequal(read_and_interp(s),t_correct));

str = 7×1 cell array {' 1 1.3' } {' 2 1.12'} {' 3 17' } {' 4 16' } {' 5 9999'} {' 6 9999'} {' 7 19' } y = 1.3000 y = 1.1200 y = 17 y = 16 y = 9999 y = 9999 y = 19 pos = 5 6 t = 1.3000 1.1200 17.0000 16.0000 17.0000 18.0000 19.0000

3   Pass
s = { ... 'Day Temp' ' 1 -5' ' 2 19' ' 3 1' ' 4 9999' ' 5 3'}; t_correct = [-5 19 1 2 3]; assert(isequal(read_and_interp(s),t_correct));

str = 5×1 cell array {' 1 -5' } {' 2 19' } {' 3 1' } {' 4 9999'} {' 5 3' } y = -5 y = 19 y = 1 y = 9999 y = 3 pos = 4 t = -5 19 1 2 3