Cody

# Problem 52. What is the next step in Conway's Life?

Solution 2011116

Submitted on 9 Nov 2019
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### Test Suite

Test Status Code Input and Output
1   Fail
A = [ ... 1 1 0 0 0 1 0 0 1 1 0 0 0 0 0 0]; B = [ ... 1 1 0 0 0 0 1 0 1 1 0 0 0 0 0 0]; assert(isequal(gameOfLife(A),B))

B = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 sur = 0 0 0 0 1 1 0 0 dec = 2 b = 1 sur = 0 1 0 1 0 0 0 0 dec = 2 b = 1 1 sur = 0 1 1 0 0 0 0 0 dec = 2 sur = 0 0 0 0 0 1 0 0 dec = 1 sur = 0 0 0 1 1 1 1 1 dec = 5 sur = 1 0 1 1 0 0 0 1 dec = 4 sur = 1 1 1 0 0 0 0 0 dec = 3 b = 1 1 0 0 0 1 sur = 0 0 0 0 1 0 1 0 dec = 2 sur = 0 0 0 0 0 1 1 0 dec = 2 b = 1 1 0 0 0 1 1 0 0 sur = 0 1 0 0 0 0 0 1 dec = 2 b = 1 1 0 0 0 1 1 1 0 sur = 1 1 0 0 0 0 0 0 dec = 2 sur = 0 0 0 0 0 1 0 0 dec = 1 sur = 0 0 0 1 1 0 1 1 dec = 4 sur = 1 0 1 1 0 0 0 1 dec = 4 sur = 1 0 1 0 0 0 0 0 dec = 2 sur = 0 0 0 0 1 0 1 0 dec = 2

Assertion failed.

2   Fail
A = [ ... 0 1 1 0 1 1 1 0 0 0 1 0 0 0 0 0]; B = [ ... 1 0 1 1 1 0 0 0 0 0 1 1 0 1 1 0]; assert(isequal(gameOfLife(A),B))

B = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 sur = 0 0 0 1 1 1 0 0 dec = 3 b = 1 sur = 0 0 1 1 1 1 0 0 dec = 4 sur = 0 1 1 1 0 0 0 0 dec = 3 b = 1 0 1 sur = 0 1 1 0 1 0 0 0 dec = 3 b = 1 0 1 1 sur = 0 0 0 0 0 1 1 0 dec = 2 b = 1 0 1 1 1 0 0 0 sur = 0 1 0 0 1 1 1 1 dec = 5 sur = 1 1 0 1 0 0 0 1 dec = 4 sur = 1 1 1 0 0 1 0 0 dec = 4 sur = 0 0 0 0 0 0 1 1 dec = 2 sur = 1 0 0 0 0 1 1 1 dec = 4 sur = 1 0 0 0 0 0 0 1 dec = 2 b = 1 0 1 1 1 0 0 0 0 0 1 0 sur = 1 1 0 0 0 0 1 0 dec = 3 b = 1 0 1 1 1 0 0 0 0 0 1 1 sur = 0 0 0 0 1 0 0 0 dec = 1 sur = 0 0 0 1 1 0 1 0 dec = 3 b = 1 0 1 1 1 0 0 0 0 0 1 1 0 1 0 0 sur = 0 0 1 1 0 0 0 1 dec = 3 b = 1 0 1 1 1 0 0 0 0 0 1 1 0 1 1 0 sur = 1 0 1 0 0 0 0 0 dec = 2

Assertion failed.