Cody

# Problem 44455. Find the average of a random sequance

Solution 1540935

Submitted on 26 May 2018 by gregory kaprov
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.

### Test Suite

Test Status Code Input and Output
1   Pass
filetext = fileread('MeanWhile.m'); assert(isempty(strfind(filetext, 'regexp')),'regexp hacks are forbidden')

2   Pass
filetext = fileread('MeanWhile.m'); assert(isempty(strfind(filetext, 'sum')),'sum() function is forbidden')

3   Pass
filetext = fileread('MeanWhile.m'); assert(isempty(strfind(filetext, 'mean')),'mean() function is forbidden')

4   Pass
rng(1); av_correct = 5.5; assert(isequal(MeanWhile(),av_correct))

x = 4 x = 7 x = 0 average = 5.5000

5   Pass
rng(2); av_correct = 4; assert(isequal(MeanWhile(),av_correct))

x = 4 x = 0 average = 4

6   Pass
rng(3); av_correct = 5.25; assert(isequal(MeanWhile(),av_correct))

x = 6 x = 7 x = 3 x = 5 x = 9 x = 9 x = 1 x = 2 x = 0 average = 5.2500

7   Pass
rng(7); av_correct = 0; assert(isequal(MeanWhile(),av_correct))

x = 0

8   Pass
rng(0); av_correct = 6.571428571428571; assert(isequal(MeanWhile(),av_correct))

x = 8 x = 9 x = 1 x = 10 x = 6 x = 1 x = 3 x = 6 x = 10 x = 10 x = 1 x = 10 x = 10 x = 5 x = 8 x = 1 x = 4 x = 10 x = 8 x = 10 x = 7 x = 0 average = 6.5714