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# Problem 44342. Spot the First Occurrence of 5

Solution 2606089

Submitted on 24 Jun 2020 by Bence Cseppento
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### Test Suite

Test Status Code Input and Output
1   Pass
assessFunctionAbsence({'regexp','regexpi','regexprep','str2num'},'FileName','locOf5.m')

2   Pass
x = 2:2:20; y_correct = 0; assert(isequal(locOf5(x),y_correct))

i = logical 0 j = 1 ans = 0

3   Pass
x = rot90(1:10); y_correct = 6; assert(isequal(locOf5(x),y_correct))

i = logical 1 j = 6 ans = 6

4   Pass
x = [1 2 5 5 9 1 5 6 5]; y_correct = [2 0 1]; assert(isequal(locOf5(x),y_correct))

i = 1×3 logical array 1 0 1 j = 2 1 1 ans = 2 0 1

5   Pass
x = magic(5); y_correct = [0 2 0 0 0]; assert(isequal(locOf5(x),y_correct))

i = 1×5 logical array 0 1 0 0 0 j = 1 2 1 1 1 ans = 0 2 0 0 0

6   Pass
x = [1 2 3 4 5; 5 4 3 2 1 2 3 5 2 1 1 5 2 6 8 3 5 2 2 5]; y_correct = [2 4 3 0 1]; assert(isequal(locOf5(x),y_correct)) % %% % x = randi([-10,10],20,1e6); % x(x==5) = 0; % p = sort(randi([0 size(x,1)],5,size(x,2))); % y_correct = p(1,:); % p(2:end,~y_correct) = 0; % [~,col,v] = find(p); % x((col-1)*size(x,1)+v) = 5; % assert(isequal(locOf5(x),y_correct))

i = 1×5 logical array 1 1 1 0 1 j = 2 4 3 1 1 ans = 2 4 3 0 1

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