Cody

# Problem 25. Remove any row in which a NaN appears

Solution 1827511

Submitted on 27 May 2019 by Thomas Tushar Dutta
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### Test Suite

Test Status Code Input and Output
1   Pass
A = [ 1 5 8 -3 NaN 14 0 6 NaN ]; B_correct = [ 1 5 8 ]; assert(isequal(remove_nan_rows(A),B_correct))

row = 3 col = 3 r = 0 0 0 j = 1 5 8 p = 1×3 logical array 0 0 0 r = 1 0 0 B = 1 5 8 j = -3 NaN 14 p = 1×3 logical array 0 1 0 r = 1 0 0 B = 1 5 8 j = 0 6 NaN p = 1×3 logical array 0 0 1 r = 1 0 0 B = 1 5 8

2   Pass
A = 1:10; B_correct = A; assert(isequal(remove_nan_rows(A),B_correct))

row = 1 col = 10 r = 0 j = 1 2 3 4 5 6 7 8 9 10 p = 1×10 logical array 0 0 0 0 0 0 0 0 0 0 r = 1 B = 1 2 3 4 5 6 7 8 9 10

3   Pass
A = [ 1 5 8 -3 NaN 14 0 6 6]; B_correct = [1 5 8; 0 6 6]; assert(isequal(remove_nan_rows(A),B_correct))

row = 3 col = 3 r = 0 0 0 j = 1 5 8 p = 1×3 logical array 0 0 0 r = 1 0 0 B = 1 5 8 j = -3 NaN 14 p = 1×3 logical array 0 1 0 r = 1 0 0 B = 1 5 8 j = 0 6 6 p = 1×3 logical array 0 0 0 r = 1 0 3 B = 1 5 8 0 6 6

4   Pass
A = [ 1 3 6 NaN 3 NaN]'; B_correct = [1 3 6 3]'; assert(isequal(remove_nan_rows(A),B_correct))

row = 6 col = 1 r = 0 0 0 0 0 0 j = 1 p = logical 0 r = 1 0 0 0 0 0 B = 1 j = 3 p = logical 0 r = 1 2 0 0 0 0 B = 1 3 j = 6 p = logical 0 r = 1 2 3 0 0 0 B = 1 3 6 j = NaN p = logical 1 r = 1 2 3 0 0 0 B = 1 3 6 j = 3 p = logical 0 r = 1 2 3 0 5 0 B = 1 3 6 3 j = NaN p = logical 1 r = 1 2 3 0 5 0 B = 1 3 6 3

5   Pass
A = [ 1 3 6 NaN; 3 4 2 1]; B_correct = [3 4 2 1]; assert(isequal(remove_nan_rows(A),B_correct))

row = 2 col = 4 r = 0 0 j = 1 3 6 NaN p = 1×4 logical array 0 0 0 1 r = 0 0 B = 0×4 empty double matrix j = 3 4 2 1 p = 1×4 logical array 0 0 0 0 r = 0 2 B = 3 4 2 1

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