Cody

# Problem 24. Function Iterator

Solution 179140

Submitted on 18 Dec 2012 by Des Mc Manus
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### Test Suite

Test Status Code Input and Output
1   Pass
%% noOp = @(x)x; fh2 = iterate_fcn(noOp, 50); assert(isequal(fh2(pi),pi));

h = @(x)x h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x))

2   Pass

h = @(x)x+1 h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x)) h = @(x)f(h(x))

3   Pass