Does anyone know how to create colors?

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Pul
Pul 2021 年 8 月 16 日
コメント済み: Pul 2021 年 8 月 17 日
Hello everyone,
How can I create/ have different colors from the standard ones (i.g. 'g','r','b','m'...)?
Thank you.
  2 件のコメント
Pul
Pul 2021 年 8 月 17 日

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採用された回答

Bjorn Gustavsson
Bjorn Gustavsson 2021 年 8 月 16 日
Colours can be specified by rgb-values in a 1-by-3 array with values between zero and one. So for example:
light_blue = [0.5 0.5 1];
plot(0:12,randn(1,12),'color',light_blue)
HTH
  7 件のコメント
Bjorn Gustavsson
Bjorn Gustavsson 2021 年 8 月 17 日
@Image Analyst, I have a poor short-time memory - but that was a bit extreme even for me.
@Pul, Great. Have a look at the file exchange for color-manipulation-tools that might help you with more demanding color-designing work - always look there for tools that solve or nearly solve your problems (it has saved me many months of work)!
Pul
Pul 2021 年 8 月 17 日
@Bjorn Gustavsson Okay, thank you!

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その他の回答 (1 件)

Image Analyst
Image Analyst 2021 年 8 月 16 日
Try this:
% Create 20 different colors according to the jet color map.
colors = jet(20);
% Plot randome data, each curve with one of the colors we created.
% Basically you have to get the color equal to one row from colors.
for k = 1 : size(colors, 1)
thisColor = colors(k, :);
y = rand(1, 5) + 2 * k; % Create some random data.
plot(y, '.-', 'Color', thisColor, 'LineWidth', 4, 'MarkerSize', 50); % Plot this one curve.
hold on; % Don't let subsequent plots blow away this one we just drew.
end
grid on;
xlabel('X');
ylabel('Y');
  3 件のコメント
Image Analyst
Image Analyst 2021 年 8 月 17 日
@Pul, like @Bjorn Gustavsson said, if you have some specific color you want to use, then you can do
light_blue = [0.5 0.5 1];
plot(1:12, randn(1,12), 'color', light_blue)
If you have created a list of lots of colors, like in my example, and, for example, you want to make the curve with the 10th color from the list, you can do
plot(y, '.-', 'Color', colors(10, :), 'LineWidth', 4, 'MarkerSize', 50); % Plot this one curve.
My demo showed that, where I plotted every color from k=1 to k=20.
Pul
Pul 2021 年 8 月 17 日
@Image Analyst Yes, clear, I got it.
Thank you!

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