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showing error in simp, too many ouput arguments

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DEBABRATA DAS
DEBABRATA DAS 2021 年 7 月 31 日
コメント済み: DEBABRATA DAS 2021 年 8 月 1 日
function SIMP(FC,M)
% IMPLICIT DOUBLE PRECISION(A-H,O-Z)
% DIMENSION FC(141)
SI=FC(1)+FC(M);
IP=4;
%C JM=M-1
for I=2:M-1
SI=SI+IP*FC(I);
IP=6-IP;
SIMP=1.0*SI/(3.0*(M-1));
end
end
when i run it, showed error using simpmson 1/3, too many output argument, i coopy it from fortran
  2 件のコメント
DEBABRATA DAS
DEBABRATA DAS 2021 年 8 月 1 日
i am using this function in another program, but not running

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回答 (1 件)

KSSV
KSSV 2021 年 8 月 1 日
You are not taking any output from the function in the code. And I suspect you are trying to call the function with an output, so this error is popping out.
Take the required variable as output from the function, as suggested by @Chunru and then call the function:
y=SIMP(FC,M) ;

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