Unable to find the number of pixels on the boundary of a ROI

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Warid Islam
Warid Islam 2021 年 6 月 30 日
コメント済み: Image Analyst 2021 年 7 月 1 日
Hi,
I want to find the number of pixels on the boundary of a ROI. I also want to find the number of pixels inside the ROI. I tried the regionprops method but it is throwing me an error message. Any suggestions would be appreciated.
myFolder = 'D:\regionGrowing_MLT\newim\Segmentation Results';
% Check to make sure that folder actually exists. Warn user if it doesn't.
if ~isfolder(myFolder)
errorMessage = sprintf('Error: The following folder does not exist:\n%s\nPlease specify a new folder.', myFolder);
uiwait(warndlg(errorMessage));
myFolder = uigetdir(); % Ask for a new one.
if myFolder == 0
% User clicked Cancel
return;
end
end
% Get a list of all files in the folder with the desired file name pattern.
filePattern = fullfile(myFolder, '*.jpg'); % Change to whatever pattern you need.
theFiles = dir(filePattern);
for k = 1 : length(theFiles)
baseFileName = theFiles(k).name;
fullFileName = fullfile(theFiles(k).folder, baseFileName);
fprintf(1, 'Now reading %s\n', fullFileName);
% Now do whatever you want with this file name,
% such as reading it in as an image array with imread()
imageArray = imread(fullFileName);
imageArray=imbinarize(imageArray);
s = regionprops(imageArray,'Area','Perimeter');
s(k,:)=s;
end
The following error message is displayed:
Unable to perform assignment because the size
of the left side is 1-by-1 and the size of
the right side is 5-by-1.
Error in im3d (line 24)
s(k,:)=s;

採用された回答

Image Analyst
Image Analyst 2021 年 6 月 30 日
Try this:
perimImage = bwperim(imageArray);
numPerimPixels = nnz(perimImage);
or
boundaries = bwboundaries(imageArray);
numPerimPixels = 0;
for k = 1 : length(boundaries)
thisBoundary = boundaries{k};
numPerimPixels = numPerimPixels + size(thisBoundary, 1);
end
  2 件のコメント
Image Analyst
Image Analyst 2021 年 7 月 1 日
bwarea gives an area weighted by the shape of the boundary, while regionprops() or nnz() is strictly a pixel count. Just depends on how you want it.
for this image
0 1
1 1
What is the area? Is it 3 pixels? Or is it half a pixel? Neither is wrong - it's just how you interpret "area". Do you consider a pixel like a little block or tile? Or are you going from pixel center to pixel center.
What is the length of the 1 region here:
0 1 1 1 0
Is it 3? Or is it 2 (going center to center)?

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