The Loops in the first picture are required, the description is below

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Matthew Worker
Matthew Worker 2021 年 6 月 28 日
編集済み: Rena Berman 2021 年 12 月 16 日
%% Suppose I have W and Theta, k=1:K .. K=(any value) let say 10
%%
Alfa_k=zeros(1,k);
Alfa_i=zeros(1,k);
Angle_h_w=zeros(1,k);
Angle_g_h_w=zeros(1,k);
n0=zeros(1,k);
for t_1=1:k
Alfa_k(t_1) = 1/(abs(H(t_1,:)*W(:,t_1)));
Angle_h_w(t_1) = angle(H(t_1,:)*W(:,t_1));
Alfa_i(t_1) = 0;
for t_2=1:k
Alfa_i(t_1) = Alfa_i(t_1) + 1/(abs(H(t_2,:)*W(:,t_2)));
end
Alfa_i(t_1) = Alfa_i(t_1) - Alfa_k(t_1); % Sum of Alfa_i
end
L_k = n*(Alfa_k./Alfa_i); % Number of IRS Elements Assigned to UE ..
% Total IRS Elements * Proportion of IRS Elements
r = n-(sum(L_k)); %The Remaining IRS Elements ..
% Are Assigned to The Weakest UE
[argvalue, argmax] = max(Alfa_k);
L_k0=L_k(argmax);
L_k0 = L_k0+r;
[Alfa_m,idx]= sort(Alfa_k, 'descend'); % sort UE
L_m = sort(L_k, 'descend');
F = F(idx,:); % sort the whole matrix using the sort idx
W = W(:,idx); % sort the whole matrix using the sort idx
for t_3=1:k
n0(t_3)=(abs(F(t_3,:)*G*W(:,t_3)))
Angle_g_h_w(t_3) = angle(F(t_3,:)*G*W(:,t_3))
end
[argval, arg_max] = max(n0)
Theta_k = -Angle_h_w-Angle_g_h_w
  3 件のコメント
Image Analyst
Image Analyst 2021 年 12 月 15 日
編集済み: Image Analyst 2021 年 12 月 15 日
Original question attached
%% Suppose I have W and Theta, k=1:K .. K=(any value) let say 10
%%
Alfa_k=zeros(1,k);
Alfa_i=zeros(1,k);
Angle_h_w=zeros(1,k);
Angle_g_h_w=zeros(1,k);
n0=zeros(1,k);
for t_1=1:k
Alfa_k(t_1) = 1/(abs(H(t_1,:)*W(:,t_1)));
Angle_h_w(t_1) = angle(H(t_1,:)*W(:,t_1));
Alfa_i(t_1) = 0;
for t_2=1:k
Alfa_i(t_1) = Alfa_i(t_1) + 1/(abs(H(t_2,:)*W(:,t_2)));
end
Alfa_i(t_1) = Alfa_i(t_1) - Alfa_k(t_1); % Sum of Alfa_i
end
L_k = n*(Alfa_k./Alfa_i); % Number of IRS Elements Assigned to UE ..
% Total IRS Elements * Proportion of IRS Elements
r = n-(sum(L_k)); %The Remaining IRS Elements ..
% Are Assigned to The Weakest UE
[argvalue, argmax] = max(Alfa_k);
L_k0=L_k(argmax);
L_k0 = L_k0+r;
[Alfa_m,idx]= sort(Alfa_k, 'descend'); % sort UE
L_m = sort(L_k, 'descend');
F = F(idx,:); % sort the whole matrix using the sort idx
W = W(:,idx); % sort the whole matrix using the sort idx
for t_3=1:k
n0(t_3)=(abs(F(t_3,:)*G*W(:,t_3)))
Angle_g_h_w(t_3) = angle(F(t_3,:)*G*W(:,t_3))
end
[argval, arg_max] = max(n0)
Theta_k = -Angle_h_w-Angle_g_h_w
Rena Berman
Rena Berman 2021 年 12 月 16 日
(Answers Dev) Restored edit

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回答 (1 件)

Walter Roberson
Walter Roberson 2021 年 6 月 29 日
Example with your second set of code. The array sizes are constructed to be consistent with your code
k = 5;
m = 3;
M = 7;
H = randi(9, k, M)
H = 5×7
6 7 4 5 2 8 4 6 1 6 7 2 1 9 8 9 7 6 7 5 1 2 3 7 6 1 1 6 6 4 7 4 3 4 8
W = randi(9, M, k)
W = 7×5
2 3 2 1 9 6 4 6 1 3 5 7 9 3 8 9 1 9 2 9 5 9 9 9 7 2 8 8 8 2 6 7 1 9 3
n = rand()
n = 0.0108
F = randi(9, k, m)
F = 5×3
2 4 5 2 9 4 7 7 8 5 3 5 2 5 2
G = randi(9, m, M)
G = 3×7
1 2 3 3 1 1 5 2 7 2 9 8 3 8 2 1 4 8 5 4 8
Alfa_k=zeros(1,k);
Alfa_i=zeros(1,k);
Angle_h_w=zeros(1,k);
Angle_g_h_w=zeros(1,k);
n0=zeros(1,k);
for t_1=1:k
Alfa_k(t_1) = 1/(abs(H(t_1,:)*W(:,t_1)));
Angle_h_w(t_1) = angle(H(t_1,:)*W(:,t_1));
Alfa_i(t_1) = 0;
for t_2=1:k
Alfa_i(t_1) = Alfa_i(t_1) + 1/(abs(H(t_2,:)*W(:,t_2)));
end
Alfa_i(t_1) = Alfa_i(t_1) - Alfa_k(t_1); % Sum of Alfa_i
end
L_k = n*(Alfa_k./Alfa_i); % Number of IRS Elements Assigned to UE ..
% Total IRS Elements * Proportion of IRS Elements
r = n-(sum(L_k)); %The Remaining IRS Elements ..
% Are Assigned to The Weakest UE
[argvalue, argmax] = max(Alfa_k);
L_k0=L_k(argmax);
L_k0 = L_k0+r;
[Alfa_m,idx]= sort(Alfa_k, 'descend'); % sort UE
L_m = sort(L_k, 'descend');
F = F(idx,:); % sort the whole matrix using the sort idx
W = W(:,idx); % sort the whole matrix using the sort idx
for t_3=1:k
n0(t_3)=(abs(F(t_3,:)*G*W(:,t_3)))
Angle_g_h_w(t_3) = angle(F(t_3,:)*G*W(:,t_3))
end
n0 = 1×5
1903 0 0 0 0
Angle_g_h_w = 1×5
0 0 0 0 0
n0 = 1×5
1903 2771 0 0 0
Angle_g_h_w = 1×5
0 0 0 0 0
n0 = 1×5
1903 2771 2025 0 0
Angle_g_h_w = 1×5
0 0 0 0 0
n0 = 1×5
1903 2771 2025 1674 0
Angle_g_h_w = 1×5
0 0 0 0 0
n0 = 1×5
1903 2771 2025 1674 3997
Angle_g_h_w = 1×5
0 0 0 0 0
[argval, arg_max] = max(n0)
argval = 3997
arg_max = 5
Theta_k = -Angle_h_w-Angle_g_h_w
Theta_k = 1×5
0 0 0 0 0
  4 件のコメント
Matthew Worker
Matthew Worker 2021 年 6 月 29 日
thank you again, do you know how to make this code compatible with the first picture, because that is the main problem for me.
Walter Roberson
Walter Roberson 2021 年 6 月 29 日
No, I do not know how to make it compatible with the first picture. If I were coding it, I would start over without your existing code.

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