# How to find the difference in values present in each row of two cell arrays of same size.

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jaah navi 2021 年 6 月 24 日
コメント済み: jaah navi 2021 年 6 月 24 日
I am having two cell arrays A and B of same size as follows
A B
1 1
1 1
1 1
1 1
1 1
[1,2] [1,2]
[1,1] [1,2]
[1,2] [1,1]
[1,2] [1,2]
[1,1] [1,2]
[1,2,2] [1,1,2]
[1,2,3] [1,2,2]
[1,2,3] [1,2,2]
[1,1,2] [1,1,2]
[1,2,2] [1,2,3]
I want to find the difference between A and B.
As the size is small I can do it manually by seeing it.
On seeing it I can find 7th ,8th, 10th, 11th, 12th, 13th, 15th rows are different.
But I having cell arrays for larger size and I am unable to do it manually.
Could anyone please help how to find the rows in a general way that are different using matlab command.

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### 採用された回答

Adam Danz 2021 年 6 月 24 日

I want to find the difference between A and B.
Set up a loop that runs isequal(A,B) on pairs from cell array A and B.
A = {1; [1 2]; [1 1]; [1 2 2]};
B = {1; [1 1]; [1 1]; 1 };
iseq = false(size(A));
for i = 1:numel(A)
iseq(i) = isequal(A{i},B{i});
end
iseq
iseq = 4×1 logical array
1 0 1 0
Or use cellfun that performs the loop above within 1 line of code,
iseq = cellfun(@isequal, A,B)
iseq = 4×1 logical array
1 0 1 0
These methods require A and B to be equal lengths.
I want to calculate the mean square error of the two cell arrays.
The pairs of vectors in A and B must have the same length.
A = {1; [1 2]; [1 1]; [1 2 2]};
B = {1; [1 1]; [1 1]; [1 2 3]};
mse = nan(size(A));
for i = 1:numel(A)
mse(i) = sum((A{i}-B{i}).^2)/numel(A{i});
end
mse
mse = 4×1
0 0.5000 0 0.3333
Or use cellfun that performs the loop above within 1 line of code,
mse = cellfun(@(A,B)sum((A-B).^2)/numel(A), A,B)
mse = 4×1
0 0.5000 0 0.3333
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jaah navi 2021 年 6 月 24 日

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